digitalmars.D.learn - Sum a lot of numbers...
- Alexandre (6/6) Jul 10 2014 Hi :)
- Alexandre (20/26) Jul 10 2014 PS: that is my code:
- Justin Whear (2/10) Jul 10 2014 A full decimal representation can be gotten with `format("%f", n);`
- Justin Whear (4/16) Jul 10 2014 And if you need more than the default 6 digits of precision after the
Hi :) I need to sum a list of numbers... but, when I calculate the sum of this numbers, I got a simplify representation of sum: 2.97506e+,12 How I can make to get the correctly representation of this number ?
Jul 10 2014
PS: that is my code:
import std.stdio, std.algorithm, std.range, std.conv;
string InsertComma(string val)
{
return val[0 .. $-2] ~ "," ~ val[$-2 .. $];
}
int main(string[] argv)
{
auto x = "oi.txt"
.File
.byLine
.filter!(line => line[0] == '1')
.map!(line => line[127 .. 140].to!real)
.sum;
auto valor = to!string(x);
write(InsertComma(valor));
readln();
return 0;
}
On Thursday, 10 July 2014 at 17:16:01 UTC, Alexandre wrote:
Hi :)
I need to sum a list of numbers... but, when I calculate the
sum of this numbers, I got a simplify representation of sum:
2.97506e+,12
How I can make to get the correctly representation of this
number ?
Jul 10 2014
On Thu, 10 Jul 2014 17:16:00 +0000, Alexandre wrote:Hi :) I need to sum a list of numbers... but, when I calculate the sum of this numbers, I got a simplify representation of sum: 2.97506e+,12 How I can make to get the correctly representation of this number ?A full decimal representation can be gotten with `format("%f", n);`
Jul 10 2014
On Thu, 10 Jul 2014 17:17:40 +0000, Justin Whear wrote:On Thu, 10 Jul 2014 17:16:00 +0000, Alexandre wrote:And if you need more than the default 6 digits of precision after the decimal, you can use a precision specifier, e.g. for 10 digits: `format ("%.10f", n)`Hi :) I need to sum a list of numbers... but, when I calculate the sum of this numbers, I got a simplify representation of sum: 2.97506e+,12 How I can make to get the correctly representation of this number ?A full decimal representation can be gotten with `format("%f", n);`
Jul 10 2014









"Alexandre" <alebencz gmail.com> 