digitalmars.D.learn - Insert a char in string
- Alexandre (7/7) Jul 10 2014 I have a string X and I need to insert a char in that string...
- Alexandre (5/12) Jul 10 2014 Sorry..
- "Marc =?UTF-8?B?U2Now7x0eiI=?= <schuetzm gmx.net> (16/31) Jul 10 2014 `std.array.insertInPlace` doesn't return anything. "In place"
- Alexandre (2/36) Jul 10 2014
- John Colvin (12/19) Jul 10 2014 insertInPlace works like this:
- Alexandre (6/28) Jul 10 2014 I used that solution:
- simendsjo (3/13) Jul 10 2014 Do you really want to insert a comma in the string, or do you want to
- Alexandre (8/23) Jul 10 2014 basically format....
- simendsjo (12/39) Jul 10 2014 I'm not sure what you're trying to do though.
- JR (3/18) Jul 11 2014 For that, one approach would be as in
- =?UTF-8?B?QWxpIMOHZWhyZWxp?= (20/27) Jul 12 2014 Here is another solution, which does not modify the original string:
I have a string X and I need to insert a char in that string... auto X = "100000000000000"; And I need to inser a ',' in position 3 of this string..., I try to use the array.insertInPlace, but, not work... I try this: auto X = "100000000000000"; auto N = X.insertInPlace(1,'0');
Jul 10 2014
Sorry.. I mean: auto X = "100000000000000"; auto N = X.insertInPlace(3,','); On Thursday, 10 July 2014 at 16:05:51 UTC, Alexandre wrote:I have a string X and I need to insert a char in that string... auto X = "100000000000000"; And I need to inser a ',' in position 3 of this string..., I try to use the array.insertInPlace, but, not work... I try this: auto X = "100000000000000"; auto N = X.insertInPlace(1,'0');
Jul 10 2014
On Thursday, 10 July 2014 at 16:20:29 UTC, Alexandre wrote:Sorry.. I mean: auto X = "100000000000000"; auto N = X.insertInPlace(3,','); On Thursday, 10 July 2014 at 16:05:51 UTC, Alexandre wrote:`std.array.insertInPlace` doesn't return anything. "In place" here means "in situ", i.e. it will not create a new string, but insert the new elements into the existing one. This operation may still reallocate, in which case the array slice you're passing in will be updated to point to the new memory. Either use this instead: auto x = "100000000000000"; auto n = x.dup; n.insertInPlace(3, ','); // or: insertInPlace(n, 3, ','); ... or use slicing and concatenating to construct a new string: auto g = x[0 .. 3] ~ ',' ~ x[3 .. $]; (Side note about style: It's common practice to use lower-case names for variables, upper-case first letters are used to denote types. But of course, that's a matter of taste.)I have a string X and I need to insert a char in that string... auto X = "100000000000000"; And I need to inser a ',' in position 3 of this string..., I try to use the array.insertInPlace, but, not work... I try this: auto X = "100000000000000"; auto N = X.insertInPlace(1,'0');
Jul 10 2014
"Alexandre" <alebencz gmail.com> Oh, I used that letters in upper case, just for a simple sample... On Thursday, 10 July 2014 at 16:32:53 UTC, Marc Schütz wrote:On Thursday, 10 July 2014 at 16:20:29 UTC, Alexandre wrote:Sorry.. I mean: auto X = "100000000000000"; auto N = X.insertInPlace(3,','); On Thursday, 10 July 2014 at 16:05:51 UTC, Alexandre wrote:`std.array.insertInPlace` doesn't return anything. "In place" here means "in situ", i.e. it will not create a new string, but insert the new elements into the existing one. This operation may still reallocate, in which case the array slice you're passing in will be updated to point to the new memory. Either use this instead: auto x = "100000000000000"; auto n = x.dup; n.insertInPlace(3, ','); // or: insertInPlace(n, 3, ','); ... or use slicing and concatenating to construct a new string: auto g = x[0 .. 3] ~ ',' ~ x[3 .. $]; (Side note about style: It's common practice to use lower-case names for variables, upper-case first letters are used to denote types. But of course, that's a matter of taste.)I have a string X and I need to insert a char in that string... auto X = "100000000000000"; And I need to inser a ',' in position 3 of this string..., I try to use the array.insertInPlace, but, not work... I try this: auto X = "100000000000000"; auto N = X.insertInPlace(1,'0');
Jul 10 2014
On Thursday, 10 July 2014 at 16:05:51 UTC, Alexandre wrote:I have a string X and I need to insert a char in that string... auto X = "100000000000000"; And I need to inser a ',' in position 3 of this string..., I try to use the array.insertInPlace, but, not work... I try this: auto X = "100000000000000"; auto N = X.insertInPlace(1,'0');insertInPlace works like this: auto X = "100000000000000"; auto X1 = X; X.insertInPlace(3, ','); assert(X == "100,000000000000"); assert(X1 == "100000000000000"); You can also do this: auto X = "100000000000000"; auto N = X[0 .. 3] ~ ',' ~ X[3 .. $]; assert(X == "100000000000000"); assert(N == "100,000000000000");
Jul 10 2014
I used that solution:
string InsertComma(string val)
{
return val[0 .. $-2] ~ "," ~ val[$-2 .. $];
}
On Thursday, 10 July 2014 at 16:23:44 UTC, John Colvin wrote:
On Thursday, 10 July 2014 at 16:05:51 UTC, Alexandre wrote:
I have a string X and I need to insert a char in that string...
auto X = "100000000000000";
And I need to inser a ',' in position 3 of this string..., I
try to use the array.insertInPlace, but, not work...
I try this:
auto X = "100000000000000";
auto N = X.insertInPlace(1,'0');
insertInPlace works like this:
auto X = "100000000000000";
auto X1 = X;
X.insertInPlace(3, ',');
assert(X == "100,000000000000");
assert(X1 == "100000000000000");
You can also do this:
auto X = "100000000000000";
auto N = X[0 .. 3] ~ ',' ~ X[3 .. $];
assert(X == "100000000000000");
assert(N == "100,000000000000");
Jul 10 2014
On 07/10/2014 06:05 PM, Alexandre wrote:I have a string X and I need to insert a char in that string... auto X = "100000000000000"; And I need to inser a ',' in position 3 of this string..., I try to use the array.insertInPlace, but, not work... I try this: auto X = "100000000000000"; auto N = X.insertInPlace(1,'0');Do you really want to insert a comma in the string, or do you want to format a number as "100,000,000,000.00"?
Jul 10 2014
basically format.... I read a cobol struct file... From pos X to Y I have a money value... but, this value don't have any format.. 000000000041415 The 15 is the cents... bascally I need to put the ( comma ), we use comma to separate the cents, here in Brazil... On Thursday, 10 July 2014 at 19:33:15 UTC, simendsjo wrote:On 07/10/2014 06:05 PM, Alexandre wrote:I have a string X and I need to insert a char in that string... auto X = "100000000000000"; And I need to inser a ',' in position 3 of this string..., I try to use the array.insertInPlace, but, not work... I try this: auto X = "100000000000000"; auto N = X.insertInPlace(1,'0');Do you really want to insert a comma in the string, or do you want to format a number as "100,000,000,000.00"?
Jul 10 2014
On 07/10/2014 09:58 PM, Alexandre wrote:basically format.... I read a cobol struct file... From pos X to Y I have a money value... but, this value don't have any format.. 000000000041415 The 15 is the cents... bascally I need to put the ( comma ), we use comma to separate the cents, here in Brazil... On Thursday, 10 July 2014 at 19:33:15 UTC, simendsjo wrote:I'm not sure what you're trying to do though. Do you need to fix the file by adding a comma at appropriate places? Or read it into D and write it to the console with your currency format? This is one way of reading in the values using slices and std.conv: import std.stdio, std.conv; void main() { immutable input = "000000000041415"; double amount = input[0..$-2].to!double(); amount += input[$-2..$].to!double() / 100; writeln(amount); }On 07/10/2014 06:05 PM, Alexandre wrote:I have a string X and I need to insert a char in that string... auto X = "100000000000000"; And I need to inser a ',' in position 3 of this string..., I try to use the array.insertInPlace, but, not work... I try this: auto X = "100000000000000"; auto N = X.insertInPlace(1,'0');Do you really want to insert a comma in the string, or do you want to format a number as "100,000,000,000.00"?
Jul 10 2014
On Thursday, 10 July 2014 at 19:33:15 UTC, simendsjo wrote:On 07/10/2014 06:05 PM, Alexandre wrote:For that, one approach would be as in http://dpaste.dzfl.pl/bddb71eb75bb.I have a string X and I need to insert a char in that string... auto X = "100000000000000"; And I need to inser a ',' in position 3 of this string..., I try to use the array.insertInPlace, but, not work... I try this: auto X = "100000000000000"; auto N = X.insertInPlace(1,'0');Do you really want to insert a comma in the string, or do you want to format a number as "100,000,000,000.00"?
Jul 11 2014
On 07/10/2014 09:05 AM, Alexandre wrote:I have a string X and I need to insert a char in that string... auto X = "100000000000000"; And I need to inser a ',' in position 3 of this string..., I try to use the array.insertInPlace, but, not work... I try this: auto X = "100000000000000"; auto N = X.insertInPlace(1,'0');Here is another solution, which does not modify the original string: import std.stdio; import std.algorithm; import std.range; import std.string; void main() { auto number = "12345678"; auto formatted = zip(number.retro, sequence!"n + 1") .map!(z => format(!(z[1] % 3) ? "%s," : "%s", z[0])) .join .retro; assert(formatted.equal("12,345,678")); } I am not happy with the .join there because I think it makes an array but I could not get it to compile with the lazy .joiner because I think it dose not look like a bidirectional range to .retro. Ali
Jul 12 2014