digitalmars.D - Behavior of "auto"
- NullTerminator (67/67) Dec 05 2007 == Repost the article of NullTerminator (NullTerminator@Hotmail.com)
- Derek Parnell (15/89) Dec 05 2007 Both 'scope' and 'auto' are poorly documented. However, the variable
- Bill Baxter (15/106) Dec 05 2007 No no no nononono!
- Kirk McDonald (19/112) Dec 05 2007 This is not true. The situation is more complex.
- NullTerminator (1/1) Dec 06 2007 Thanks to you and Bill Baxter from post 63092. That makes a lot more se...
- bearophile (75/75) Dec 06 2007 To experiment I have modified your code some (this tread probably belong...
- Sean Kelly (6/51) Dec 06 2007 ...
- bearophile (13/15) Dec 07 2007 This is a reduced and simplified version that shows the same thing:
- Sean Kelly (3/19) Dec 07 2007 Please submit a ticket for it if you haven't already :-)
== Repost the article of NullTerminator (NullTerminator Hotmail.com)
== Posted at 2007/12/06 01:07 to D
A strange effect of using auto:
The following code:
import std.stdio;
class Test {
this() {
printf("Created\n");
}
~this() {
printf("Destroyed\n");
}
}
int main(char[][] args){
for (int n = 0; n < 10; n++)
Test t = new Test();
return 0;
}
produces the following output:
Created
Created
Created
Created
Created
Created
Created
Created
Created
Created
Destroyed
Destroyed
Destroyed
Destroyed
Destroyed
Destroyed
Destroyed
Destroyed
Destroyed
Destroyed
where as changing the line:
Test t = new Test();
to:
auto Test t = new Test();
produces:
Created
Destroyed
Created
Destroyed
Created
Destroyed
Created
Destroyed
Created
Destroyed
Created
Destroyed
Created
Destroyed
Created
Destroyed
Created
Destroyed
Created
Destroyed
As I understand it, one would expect this to be the effect of "scope," not
"auto." Can someone explain why this happens?
Thanks in advance.
Dec 05 2007
On Thu, 6 Dec 2007 06:20:53 +0000 (UTC), NullTerminator wrote:
== Repost the article of NullTerminator (NullTerminator Hotmail.com)
== Posted at 2007/12/06 01:07 to D
A strange effect of using auto:
The following code:
import std.stdio;
class Test {
this() {
printf("Created\n");
}
~this() {
printf("Destroyed\n");
}
}
int main(char[][] args){
for (int n = 0; n < 10; n++)
Test t = new Test();
return 0;
}
produces the following output:
Created
Created
Created
Created
Created
Created
Created
Created
Created
Created
Destroyed
Destroyed
Destroyed
Destroyed
Destroyed
Destroyed
Destroyed
Destroyed
Destroyed
Destroyed
where as changing the line:
Test t = new Test();
to:
auto Test t = new Test();
produces:
Created
Destroyed
Created
Destroyed
Created
Destroyed
Created
Destroyed
Created
Destroyed
Created
Destroyed
Created
Destroyed
Created
Destroyed
Created
Destroyed
Created
Destroyed
As I understand it, one would expect this to be the effect of "scope," not
"auto." Can someone explain why this happens?
Both 'scope' and 'auto' are poorly documented. However, the variable
declared with an 'auto' is scoped to the block it is declared in and is
destroyed when going out of scope. In effect 'auto' is shorthand for 'scope
<type>' ...
That is to say ...
auto t = new Test();
is equivalent to ...
scope Test t = new Test();
--
Derek
(skype: derek.j.parnell)
Melbourne, Australia
6/12/2007 5:51:16 PM
Dec 05 2007
Derek Parnell wrote:On Thu, 6 Dec 2007 06:20:53 +0000 (UTC), NullTerminator wrote:No no no nononono! auto Test t = new Test(); is equivalent to scope Test t = new Test(); but auto t = new Test(); is a regular local (aka "automatic") variable who's type is deduced because none is explicitly specified. The reason "auto Test t" compiles at all is because that was the syntax for scoped allocation before everyone and their dog complained about how confusing and misleading it was. Walter changed it to 'scope' but unfortunately the old syntax still works for some reason. It really should only work with -d set. --bb== Repost the article of NullTerminator (NullTerminator Hotmail.com) == Posted at 2007/12/06 01:07 to D A strange effect of using auto: The following code: import std.stdio; class Test { this() { printf("Created\n"); } ~this() { printf("Destroyed\n"); } } int main(char[][] args){ for (int n = 0; n < 10; n++) Test t = new Test(); return 0; } produces the following output: Created Created Created Created Created Created Created Created Created Created Destroyed Destroyed Destroyed Destroyed Destroyed Destroyed Destroyed Destroyed Destroyed Destroyed where as changing the line: Test t = new Test(); to: auto Test t = new Test(); produces: Created Destroyed Created Destroyed Created Destroyed Created Destroyed Created Destroyed Created Destroyed Created Destroyed Created Destroyed Created Destroyed Created Destroyed As I understand it, one would expect this to be the effect of "scope," not "auto." Can someone explain why this happens?Both 'scope' and 'auto' are poorly documented. However, the variable declared with an 'auto' is scoped to the block it is declared in and is destroyed when going out of scope. In effect 'auto' is shorthand for 'scope <type>' ... That is to say ... auto t = new Test(); is equivalent to ... scope Test t = new Test();
Dec 05 2007
Derek Parnell wrote:On Thu, 6 Dec 2007 06:20:53 +0000 (UTC), NullTerminator wrote:This is not true. The situation is more complex. Prior to DMD 0.174, 'auto' was used for both type inference and scoped destruction. That is to say, this: auto obj = new C; // infer the type of 'obj' Was different than this: auto C obj = new C; // destroy 'obj' at the end of scope This behavior was considered confusing enough that the 'scope' keyword (which was already in the language for scope guards) was allowed in place of auto in the latter case: scope C obj = new C; // destroy 'obj' at the end of scope The use of 'auto' to mean scoped destruction was promptly forgotten as fast as people could. However, as the original poster discovered, this meaning is still allowed. -- Kirk McDonald http://kirkmcdonald.blogspot.com Pyd: Connecting D and Python http://pyd.dsource.org== Repost the article of NullTerminator (NullTerminator Hotmail.com) == Posted at 2007/12/06 01:07 to D A strange effect of using auto: The following code: import std.stdio; class Test { this() { printf("Created\n"); } ~this() { printf("Destroyed\n"); } } int main(char[][] args){ for (int n = 0; n < 10; n++) Test t = new Test(); return 0; } produces the following output: Created Created Created Created Created Created Created Created Created Created Destroyed Destroyed Destroyed Destroyed Destroyed Destroyed Destroyed Destroyed Destroyed Destroyed where as changing the line: Test t = new Test(); to: auto Test t = new Test(); produces: Created Destroyed Created Destroyed Created Destroyed Created Destroyed Created Destroyed Created Destroyed Created Destroyed Created Destroyed Created Destroyed Created Destroyed As I understand it, one would expect this to be the effect of "scope," not "auto." Can someone explain why this happens?Both 'scope' and 'auto' are poorly documented. However, the variable declared with an 'auto' is scoped to the block it is declared in and is destroyed when going out of scope. In effect 'auto' is shorthand for 'scope <type>' ... That is to say ... auto t = new Test(); is equivalent to ... scope Test t = new Test();
Dec 05 2007
Thanks to you and Bill Baxter from post 63092. That makes a lot more sense now.
Dec 06 2007
To experiment I have modified your code some (this tread probably belongs to
D.learn):
import std.gc;
class Test {
int i;
this(int i) {
this.i = i;
printf("%d created\n", this.i); }
~this() { printf("%d destroyed\n", this.i); }
}
void main() {
printf("Part 1 ----------\n");
for (int i = 0; i < 5; i++)
auto t = new Test(i);
printf("Part1 end ----------\n\n");
printf("Part 2 ----------\n");
for (int i = 0; i < 5; i++)
auto scope t = new Test(i+5);
printf("Part 2 end ----------\n\n");
printf("Part3 ----------\n");
foreach(i, _; new byte[5])
auto scope t = new Test(i+10);
printf("Part 3 end ----------\n\n");
printf("Part4 ----------\n");
foreach(i, _; new byte[5])
auto t = new Test(i+15);
printf("Part 4 end ----------\n\n");
std.gc.fullCollect();
}
And now I too don't fully understand the results (DMD v1.024):
Part 1 ----------
0 created
1 created
2 created
3 created
4 created
Part1 end ----------
Part 2 ----------
5 created
5 destroyed
6 created
6 destroyed
7 created
7 destroyed
8 created
8 destroyed
9 created
9 destroyed
Part 2 end ----------
Part3 ----------
10 created
11 created
12 created
13 created
14 created
Part 3 end ----------
Part4 ----------
15 created
16 created
17 created
18 created
19 created
Part 4 end ----------
18 destroyed
17 destroyed
16 destroyed
15 destroyed
3 destroyed
2 destroyed
1 destroyed
0 destroyed
19 destroyed
4 destroyed
I don't see where the 10-14 objects are deallocated (I have added a
fullCollect, but it just scrambles the order of the those last deallocations).
Bye,
bearophile
Dec 06 2007
bearophile wrote:To experiment I have modified your code some (this tread probably belongs to D.learn): import std.gc; class Test { int i; this(int i) { this.i = i; printf("%d created\n", this.i); } ~this() { printf("%d destroyed\n", this.i); } } void main() { printf("Part 1 ----------\n"); for (int i = 0; i < 5; i++) auto t = new Test(i); printf("Part1 end ----------\n\n"); printf("Part 2 ----------\n"); for (int i = 0; i < 5; i++) auto scope t = new Test(i+5); printf("Part 2 end ----------\n\n"); printf("Part3 ----------\n"); foreach(i, _; new byte[5]) auto scope t = new Test(i+10); printf("Part 3 end ----------\n\n"); printf("Part4 ----------\n"); foreach(i, _; new byte[5]) auto t = new Test(i+15); printf("Part 4 end ----------\n\n"); std.gc.fullCollect(); }...Part3 ---------- 10 created 11 created 12 created 13 created 14 created Part 3 end ----------...I don't see where the 10-14 objects are deallocated (I have added a fullCollect, but it just scrambles the order of the those last deallocations).I'd guess that this is a bug, and is related to the extra work the compiler does for foreach loops. Sean
Dec 06 2007
Sean Kelly:I'd guess that this is a bug, and is related to the extra work the compiler does for foreach loops.This is a reduced and simplified version that shows the same thing: class Foo { ~this() { printf("Destroyed\n"); } } void main() { foreach(i; new int[1]) scope Foo f = new Foo(); } Bye, bearophile
Dec 07 2007
bearophile wrote:Sean Kelly:Please submit a ticket for it if you haven't already :-) SeanI'd guess that this is a bug, and is related to the extra work the compiler does for foreach loops.This is a reduced and simplified version that shows the same thing: class Foo { ~this() { printf("Destroyed\n"); } } void main() { foreach(i; new int[1]) scope Foo f = new Foo(); }
Dec 07 2007









Bill Baxter <dnewsgroup billbaxter.com> 