• Manfred Nowak (63/63) Jan 15 2004 This code compiles and delivers the right result

Manfred Nowak <svv1999 hotmail.com> writes:

This code compiles and delivers the right result
<code>
import std.regexp;
import std.string;

void main()
{
  RegExp octDigit=new RegExp("[0-7]",null);
  char[] s="1234";
  char[] o;

  o=format("%d %s\n",octDigit.test(s[2..4]),s[2..4]);
  printf(o);
  o=format("%d %s\n",octDigit.test(s[1..4]),s[1..4]);
  printf(o);
  o=format("%d %s\n",octDigit.test(s[0..4]),s[0..4]);
  printf(o);
}
</code>


But changing the order of evaluation:
<code>
import std.regexp;
import std.string;

void main()
{
  RegExp octDigit=new RegExp("[0-7]",null);
  char[] s="1234";
  char[] o;

  o=format("%d %s\n",octDigit.test(s[0..4]),s[0..4]);
  printf(o);
  o=format("%d %s\n",octDigit.test(s[1..4]),s[1..4]);
  printf(o);
  o=format("%d %s\n",octDigit.test(s[2..4]),s[2..4]);
  printf(o);
}
</code>

Leads to: "Internal error: ..\ztc\cgcod.c 2241"


Deleting the superfluos slicing `[0..4]':
<code>
import std.regexp;
import std.string;

void main()
{
  RegExp octDigit=new RegExp("[0-7]",null);
  char[] s="1234";
  char[] o;

  o=format("%d %s\n",octDigit.test(s),s);
  printf(o);
  o=format("%d %s\n",octDigit.test(s[1..4]),s[1..4]);
  printf(o);
  o=format("%d %s\n",octDigit.test(s[2..4]),s[2..4]);
  printf(o);
}
</code>

again compiles but delivers the wrong result `0' at the third 
execution:
<protocol>
1 1234
1 234
0 34
</protocol>

So long.
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