digitalmars.D - randomSample with unknown length
- Magnus Lie Hetland (21/21) Feb 02 2011 Reading the doc for std.random.randomSample, I saw that "The total
- Andrei Alexandrescu (10/29) Feb 02 2011 I posted a problem solved by the algorithm above (and others, more
- Simen kjaeraas (8/10) Feb 02 2011 Done. No comments or unittests yet, though.
- Magnus Lie Hetland (8/16) Feb 02 2011 Sure. I was just thinking that you could have a version for the cases
Reading the doc for std.random.randomSample, I saw that "The total length of r must be known". There are rather straightforward algorithms for drawing random samples *without* knowing this. This might be useful if one wants to support input ranges, I guess? Take, for example, the method described by Knuth (TAoP 2), for selecting n elements uniformly at random from an input range: - Select the first n elements as the current sample. - Each subsequent element is rejected with a probability of 1 - n/t, where t is the number seen so far. - If a new item is selected, it replaces a random item in the current sample. A cool property of this is that at any time, the current sample is one drawn randomly (i.e., uniformly, without replacement) from the items you've seen so far, so you could really stop at any point. That is, stop iterating over the input; you can't really give the output as a small-footprint range here (as far as I can see). Seems you have to allocate room for n pointers. (Or you *could* just keep track of which objects were swapped in -- might be worth the overhead if n is large compared to the input size.) -- Magnus Lie Hetland http://hetland.org
Feb 02 2011
On 2/2/11 6:03 AM, Magnus Lie Hetland wrote:Reading the doc for std.random.randomSample, I saw that "The total length of r must be known". There are rather straightforward algorithms for drawing random samples *without* knowing this. This might be useful if one wants to support input ranges, I guess? Take, for example, the method described by Knuth (TAoP 2), for selecting n elements uniformly at random from an input range: - Select the first n elements as the current sample. - Each subsequent element is rejected with a probability of 1 - n/t, where t is the number seen so far. - If a new item is selected, it replaces a random item in the current sample. A cool property of this is that at any time, the current sample is one drawn randomly (i.e., uniformly, without replacement) from the items you've seen so far, so you could really stop at any point. That is, stop iterating over the input; you can't really give the output as a small-footprint range here (as far as I can see). Seems you have to allocate room for n pointers. (Or you *could* just keep track of which objects were swapped in -- might be worth the overhead if n is large compared to the input size.)I posted a problem solved by the algorithm above (and others, more sophisticated ones) as a challenge to this group a couple of years ago. randomSample is designed to subsample a large stream in constant space and without needing to scan the entire stream in order to output the first element. I used in in my dissertation where e.g. I had to select 100K samples from a stream of many millions. Having a reservoir sample available would be nice. I'd be thrilled if you coded up a reservoirSample(r, n) function for addition to std.random. Andrei
Feb 02 2011
Andrei Alexandrescu <SeeWebsiteForEmail erdani.org> wrote:Having a reservoir sample available would be nice. I'd be thrilled if you coded up a reservoirSample(r, n) function for addition to std.random.Done. No comments or unittests yet, though. randomSampleRange( R, num ) takes num samples from an input range, and keeps a reservoir that is updated as you traverse the range (lazy, if you wish). randomSample( R, num ) takes num samples from all over a range (eager). -- Simen
Feb 02 2011
On 2011-02-02 16:32:25 +0100, Andrei Alexandrescu said:randomSample is designed to subsample a large stream in constant space and without needing to scan the entire stream in order to output the first element.Sure. I was just thinking that you could have a version for the cases where there was no end in sight :)I used in in my dissertation where e.g. I had to select 100K samples from a stream of many millions.Cool.Having a reservoir sample available would be nice. I'd be thrilled if you coded up a reservoirSample(r, n) function for addition to std.random.Seems Simen beat me to it :) -- Magnus Lie Hetland http://hetland.org
Feb 02 2011