digitalmars.D - non-instance accessibility of immutable instance variables with initializers
- Timon Gehr (15/15) Jun 03 2012 DMD 2.059:
- Simen Kjaeraas (9/24) Jun 03 2012 It gets worse:
- Artur Skawina (8/42) Jun 03 2012 It's completely broken - the struct layout depends on whether the field ...
- Timon Gehr (5/47) Jun 03 2012 I see. The intended behaviour seems to be that immutable implies static
DMD 2.059: struct S{ immutable x = [1]; immutable y = 1; } void main(){ writeln(S.x); // ok writeln(&S.x); // ok writeln(S.y); // ok // writeln(&S.y); // error with(S) writeln(&y); // ok (but resulting pointer is wrong) } This behaviour is obviously buggy, but I am not sure to what extent. What is the intended behaviour? Should initialised immutable instance variables be accessible without an instance at all?
Jun 03 2012
On Sun, 03 Jun 2012 15:40:32 +0200, Timon Gehr <timon.gehr gmx.ch> wrote:DMD 2.059: struct S{ immutable x = [1]; immutable y = 1; } void main(){ writeln(S.x); // ok writeln(&S.x); // ok writeln(S.y); // ok // writeln(&S.y); // error with(S) writeln(&y); // ok (but resulting pointer is wrong) } This behaviour is obviously buggy, but I am not sure to what extent. What is the intended behaviour? Should initialised immutable instance variables be accessible without an instance at all?It gets worse: writeln(S.sizeof); // 1, which is the same as an empty struct S s; writeln(&s); // Gives a good pointer writeln(&s.x); // Gives a completely different pointer // (the same as for &S.x) This should show clearly that the compiler treats these as enum instead of immutable, and thus do not leave them in the struct.
Jun 03 2012
On 06/03/12 17:31, Simen Kjaeraas wrote:On Sun, 03 Jun 2012 15:40:32 +0200, Timon Gehr <timon.gehr gmx.ch> wrote:It's completely broken - the struct layout depends on whether the field has an initializer - something that may be legal for classes [1], but isn't for structs. Requiring 'static' is fine, there's no need for that kind of compiler magic. The attempts to access TYPE.field using my old GDC result in ICE, BTW. artur [1] and i'm not saying it's good idea, just the way it currently is.DMD 2.059: struct S{ immutable x = [1]; immutable y = 1; } void main(){ writeln(S.x); // ok writeln(&S.x); // ok writeln(S.y); // ok // writeln(&S.y); // error with(S) writeln(&y); // ok (but resulting pointer is wrong) } This behaviour is obviously buggy, but I am not sure to what extent. What is the intended behaviour? Should initialised immutable instance variables be accessible without an instance at all?It gets worse: writeln(S.sizeof); // 1, which is the same as an empty struct S s; writeln(&s); // Gives a good pointer writeln(&s.x); // Gives a completely different pointer // (the same as for &S.x) This should show clearly that the compiler treats these as enum instead of immutable, and thus do not leave them in the struct.
Jun 03 2012
On 06/03/2012 06:18 PM, Artur Skawina wrote:On 06/03/12 17:31, Simen Kjaeraas wrote:I see. The intended behaviour seems to be that immutable implies static on fields with initializers. Thanks! Filed: http://d.puremagic.com/issues/show_bug.cgi?id=8192On Sun, 03 Jun 2012 15:40:32 +0200, Timon Gehr<timon.gehr gmx.ch> wrote:It's completely broken - the struct layout depends on whether the field has an initializer - something that may be legal for classes [1], but isn't for structs. Requiring 'static' is fine, there's no need for that kind of compiler magic. The attempts to access TYPE.field using my old GDC result in ICE, BTW. artur [1] and i'm not saying it's good idea, just the way it currently is.DMD 2.059: struct S{ immutable x = [1]; immutable y = 1; } void main(){ writeln(S.x); // ok writeln(&S.x); // ok writeln(S.y); // ok // writeln(&S.y); // error with(S) writeln(&y); // ok (but resulting pointer is wrong) } This behaviour is obviously buggy, but I am not sure to what extent. What is the intended behaviour? Should initialised immutable instance variables be accessible without an instance at all?It gets worse: writeln(S.sizeof); // 1, which is the same as an empty struct S s; writeln(&s); // Gives a good pointer writeln(&s.x); // Gives a completely different pointer // (the same as for&S.x) This should show clearly that the compiler treats these as enum instead of immutable, and thus do not leave them in the struct.
Jun 03 2012