• aerto (10/10) Jan 02 2018 Hello and happy new year im new in d so i have a question
• visitor (19/22) Jan 02 2018 if you can rewrite your users.txt file like so :
• Muld (4/27) Jan 02 2018 This means you need to recompile your code any time you want to
• Tony (25/35) Jan 02 2018 This seems to work (on Linux with no error checking) but is using
• codephantom (10/12) Jan 03 2018 the replacement is known as 'programming' ;-)
• Tony (56/70) Jan 04 2018 OK, thanks. The removechars() note about deprecation said to use
• codephantom (8/14) Jan 04 2018 If I see this in someones code - import std.regex; - it

aerto <investotxrt gmail.com> writes:

Hello and happy new year im new in d so i have a question

i have into a txt file named users.txt the bellow

["admin":"123456789"]
["test":"test345"]


im my app

string[string] data;

so i need to load users.txt content into data in order to be able 
to run


writeln(data["admin"]); // i want this to print 123456789
writeln(data["test"]); // i want this to print test345

visitor <visitor gmail.com> writes:

On Tuesday, 2 January 2018 at 22:08:52 UTC, aerto wrote:
 Hello and happy new year im new in d so i have a question

 writeln(data["admin"]); // i want this to print 123456789
 writeln(data["test"]); // i want this to print test345

if you can rewrite your users.txt file like so :

["admin":"123456789",
"test":"test345"]

with the help of import expression /-J command line switch (or 
dub stringImportPaths)
https://dlang.org/spec/expression.html#import_expressions
"dmd -release -J. yourfile.d" for example if users.txt is in same 
folder

import std.stdio;

string[string] data;

static this() {
     // of course you could also do this in main()
     data = mixin(import("users.txt"));
}

void main(string[] args)
{
     writefln("test => %s", data["test"]);
}

Muld <2 2.2> writes:

On Tuesday, 2 January 2018 at 23:25:21 UTC, visitor wrote:
 On Tuesday, 2 January 2018 at 22:08:52 UTC, aerto wrote:
 Hello and happy new year im new in d so i have a question

 writeln(data["admin"]); // i want this to print 123456789
 writeln(data["test"]); // i want this to print test345

 if you can rewrite your users.txt file like so :

 ["admin":"123456789",
 "test":"test345"]

 with the help of import expression /-J command line switch (or 
 dub stringImportPaths)
 https://dlang.org/spec/expression.html#import_expressions
 "dmd -release -J. yourfile.d" for example if users.txt is in 
 same folder

 import std.stdio;

 string[string] data;

 static this() {
     // of course you could also do this in main()
     data = mixin(import("users.txt"));
 }

 void main(string[] args)
 {
     writefln("test => %s", data["test"]);
 }

This means you need to recompile your code any time you want to 
change users.txt. Which would not be ideal from a user's 
perspective of the program.

Tony <tonytdominguez aol.com> writes:

On Tuesday, 2 January 2018 at 22:08:52 UTC, aerto wrote:
 Hello and happy new year im new in d so i have a question

 i have into a txt file named users.txt the bellow

 ["admin":"123456789"]
 ["test":"test345"]


 im my app

 string[string] data;

 so i need to load users.txt content into data in order to be 
 able to run


 writeln(data["admin"]); // i want this to print 123456789
 writeln(data["test"]); // i want this to print test345

This seems to work (on Linux with no error checking) but is using 
the deprecated removechars() which gets deleted May 2018. There 
should be a simple fix using std.regex.replaceAll but I can't 
even get a successful compile right now (templates aren't 
deducing). Someone else should know what the correct replacement 
is for removechars().

import std.stdio;
import std.string;
import std.algorithm;


void main()
{
    string line;
    string[string] data;
    auto f = File("users.txt","r");
    while ((line = f.readln('\n')) !is null)
    {

       string trimmed = removechars!string(line,"[\\[\\]\"\n\r]");
       auto fields = findSplit(trimmed,":");
       data[fields[0]] = fields[2];
    }
    writeln(data);
    writeln("data for key admin:",data["admin"]);
    f.close();
}

codephantom <me noyb.com> writes:

On Wednesday, 3 January 2018 at 05:45:32 UTC, Tony wrote:
 Someone else should know what the correct replacement
 is for removechars().

the replacement is known as 'programming' ;-)

//string trimmed = removechars!string(line,"[\\[\\]\"\n\r]");
string trimmed;
foreach(c; line)
{
     if(c != '[' && c != ']' && c != '\"' && c != '\r' && c != 
'\n' )
       trimmed ~= c;
}

Tony <tonytdominguez aol.com> writes:

On Thursday, 4 January 2018 at 05:52:35 UTC, codephantom wrote:
 On Wednesday, 3 January 2018 at 05:45:32 UTC, Tony wrote:
 Someone else should know what the correct replacement
 is for removechars().

 the replacement is known as 'programming' ;-)

 //string trimmed = removechars!string(line,"[\\[\\]\"\n\r]");
 string trimmed;
 foreach(c; line)
 {
     if(c != '[' && c != ']' && c != '\"' && c != '\r' && c != 
 '\n' )
       trimmed ~= c;
 }

OK, thanks. The removechars() note about deprecation said to use 
std.regex instead so I have been looking at that and after a 
struggle did make some use of std.regex.replaceAll. Reminded me 
of the famous Jamie Zawinski quote: "Some people, when confronted 
with a problem, think "I know, I'll use regular expressions." Now 
they have two problems.

import std.stdio;
import std.string;
import std.algorithm;
import std.regex;
import std.file;
import std.format : format;

void checkLine(string line,long line_number)
{
    // not expecting any whitespace or extra colons. Each line:
    // ["key":"value"]

    long colon_pos = std.string.indexOf(line,':');
    assert(colon_pos != -1,format("ERROR: no colon on line 
%s",line_number));
    long splitter_string_pos = std.string.indexOf(line,"\":\"");
    assert(splitter_string_pos != -1,
	  format("ERROR: line %s missing quote(s) adjacent to 
:",line_number));
    assert(line[0..2] == "[\"",format("ERROR: no [\" at line %s 
start",line_number));
    assert(line[line.length - 2 .. line.length] == "\"]",
	  format("ERROR: no \"] at end of line %s",line_number));
}

void main()
{
    string[string] data;
    string filename = "users.txt";
    assert( std.file.exists(filename), format("ERROR: file %s not 
found",filename));
    auto f = std.stdio.File("users.txt","r");
    scope(exit) { f.close(); }
    string line = f.readln!();
    long line_number = 0;
    while ( line !is null)
    {
       import std.uni : lineSep;
       line_number++;
       checkLine(std.string.chomp!(string)(line),line_number);
       auto fields  = std.algorithm.findSplit(line,"\":\"");
       string key   = 
std.regex.replaceAll(fields[0],regex(`^\["(.*)$`),"$1");
       string value = 
std.regex.replaceAll(fields[2],regex(`^(.*)"\]\r?\n$`),"$1");
       data[key] = value;
       line = f.readln!();   				
    }
    writeln(data);
    writeln("value for key admin:",data["admin"]);
    writeln("value for key test:",data["test"]);
}

codephantom <me noyb.com> writes:

On Thursday, 4 January 2018 at 08:39:04 UTC, Tony wrote:
 OK, thanks. The removechars() note about deprecation said to 
 use std.regex instead so I have been looking at that and after 
 a struggle did make some use of std.regex.replaceAll. Reminded 
 me of the famous Jamie Zawinski quote: "Some people, when 
 confronted with a problem, think "I know, I'll use regular 
 expressions." Now they have two problems.

If I see this in someones code  - import std.regex; - it 
immediately causes me concerns - not just because I do not 
understand it, but there is no way for me to know whether that 
person understands it.

So that is a well known quote..for a reason ;-)

I've had a long career without regex, and I plan to keep it that 
way.