• BCS (7/7) May 08 2008 T[] RemoveAt(T)(ref T[] dat, int i)
• BCS (5/15) May 08 2008 T RemoveAt(T)(ref T dat, int i)
• Max Samukha (12/19) May 09 2008 The function should return an array.

BCS <ao pathlink.com> writes:

T[] RemoveAt(T)(ref T[] dat, int i)
{
	dat = dat[0..i] ~ dat[i+1..$];
}


char[][] args

args.RemoveAt(0);

(D v1)

BCS <ao pathlink.com> writes:

Reply to Benjamin,

 T[] RemoveAt(T)(ref T[] dat, int i)
 {
 dat = dat[0..i] ~ dat[i+1..$];
 }
 char[][] args
 
 args.RemoveAt(0);
 
 (D v1)
 


T RemoveAt(T)(ref T dat, int i)
{
 return dat = dat[0..i] ~ dat[i+1..$];
}

Max Samukha <nospam nospam.com> writes:

On Thu, 8 May 2008 22:14:06 +0000 (UTC), BCS <ao pathlink.com> wrote:

T[] RemoveAt(T)(ref T[] dat, int i)
{
	dat = dat[0..i] ~ dat[i+1..$];
}


char[][] args

args.RemoveAt(0);

(D v1)

The function should return an array.

T[] RemoveAt(T)(ref T[] dat, int i)
{
     dat = dat[0..i] ~ dat[i+1..$];
      return dat;
} 

or 

void RemoveAt(T)(ref T[] dat, int i)
{
     dat = dat[0..i] ~ dat[i+1..$];
}