• Erik Smith (10/10) May 03 2016 C++ has template templates. I'm not sure how to achieve the same
• ag0aep6g (4/11) May 03 2016 static void call(alias f, A...)(A a) {
• Alex Parrill (13/23) May 03 2016 You're close.
• Erik Smith (1/13) May 03 2016 Works. Thanks!

Erik Smith <erik cruiserhouse.com> writes:

C++ has template templates.  I'm not sure how to achieve the same 
effect where (in example below) the template function myVariadic 
is passed to another function.

         void myVaridatic(A...)(A a) {}

         static void call(alias F,A...)(F f,A a) {
             f(a);
         }

         void foo() {
             call(myVaridatic,1,2,3);
         }

ag0aep6g <anonymous example.com> writes:

On 03.05.2016 23:31, Erik Smith wrote:
          void myVaridatic(A...)(A a) {}

Aside: I think it's "variadic", not "varidatic".

          static void call(alias F,A...)(F f,A a) {

static void call(alias f, A...)(A a) {

              f(a);
          }

          void foo() {
              call(myVaridatic,1,2,3);

call!myVaridatic(1, 2, 3);

          }

Alex Parrill <initrd.gz gmail.com> writes:

On Tuesday, 3 May 2016 at 21:31:35 UTC, Erik Smith wrote:
 C++ has template templates.  I'm not sure how to achieve the 
 same effect where (in example below) the template function 
 myVariadic is passed to another function.

         void myVaridatic(A...)(A a) {}

         static void call(alias F,A...)(F f,A a) {
             f(a);
         }

         void foo() {
             call(myVaridatic,1,2,3);
         }

You're close.

An `alias` template parameter can be any symbol, including a 
template. But you can't pass in a template as a runtime 
parameter, so having `F f` in your parameters list is wrong 
(there's nothing to pass anyway; you already have the template, 
which is F).

static void call(alias F, A...)(A a) {
     F(a);
}

Then instantiate and call the `call` function with the template 
you want:

call!myVariadict(1,2,3);

Erik Smith <erik cruiserhouse.com> writes:

 You're close.

 An `alias` template parameter can be any symbol, including a 
 template. But you can't pass in a template as a runtime 
 parameter, so having `F f` in your parameters list is wrong 
 (there's nothing to pass anyway; you already have the template, 
 which is F).

 static void call(alias F, A...)(A a) {
     F(a);
 }

 Then instantiate and call the `call` function with the template 
 you want:

 call!myVariadict(1,2,3);


Works. Thanks!