• Kagamin (9/9) Jun 14 ```
• Forum User (16/26) Jun 14 ```
• Kagamin (1/1) Jun 15 If b<10, `'0'+b` is returned.

Kagamin <spam here.lot> writes:

```
char BitsToChar(in uint bit5)
{
	const uint b=bit5&0x1f;
	return b<10?'0'+b:'a'+(b-10);
}
```
This code can't implicitly convert to char, but a version without 
parentheses `'a'+b-10` can. Is this intended or I miss something?

Forum User <forumuser example.com> writes:

On Sunday, 14 June 2026 at 09:06:13 UTC, Kagamin wrote:
 ```
 char BitsToChar(in uint bit5)
 {
 	const uint b=bit5&0x1f;
 	return b<10?'0'+b:'a'+(b-10);
 }
 ```
 This code can't implicitly convert to char, but a version 
 without parentheses `'a'+b-10` can. Is this intended or I miss 
 something?

```
    (b - 10)
```

has type `uint` and wraps if `b` < 10.

```
    'a' + b - 10
```

is evaluated left to right, `b` is < 32, so `'a' + b` is < 129. 
Substract 10 and the expression is < 119. It fits in the range of 
char.

But the whole thing is questionable:

    - Drop the `const` in `b`'s declaration and the Error shows up 
in
      the unparenthesized version, too.

    - try `+127` and `+128` instead of `-10`.

Kagamin <spam here.lot> writes:

If b<10, `'0'+b` is returned.