• Caligo (18/18) Mar 30 2011 I have a struct that looks something like this:
• =?ISO-8859-1?Q?Ali_=C7ehreli?= (27/45) Mar 30 2011 Template template parameter means exactly that: a template parameter is
• Caligo (11/11) Mar 31 2011 I should have been more clear, but my actual question is how do I
• =?ISO-8859-1?Q?Ali_=C7ehreli?= (19/38) Mar 31 2011 With the help of function template parameter deduction, I was able to do...

Caligo <iteronvexor gmail.com> writes:

I have a struct that looks something like this:

struct Box(T, size_t width, size_t height){

alias width width_;
alias height height_;

//do something with a Box of different size
  void Fun( B )(B b){
    // using width and height of b
    B.width_;
    B.height_;
  }
}

auto b1 = Box!(double, 2, 7)();
auto b2 = Box!(double, 3, 4)();
b1.Fun(b2);

I think the technical name for this is template template parameter.
Using the above I'm able to do what I need to do, but is there a
better way?
and should I use alias or enum?

=?ISO-8859-1?Q?Ali_=C7ehreli?= <acehreli yahoo.com> writes:

On 03/30/2011 04:32 PM, Caligo wrote:
 I have a struct that looks something like this:

 struct Box(T, size_t width, size_t height){

 alias width width_;
 alias height height_;

 //do something with a Box of different size
    void Fun( B )(B b){
      // using width and height of b
      B.width_;
      B.height_;
    }
 }

 auto b1 = Box!(double, 2, 7)();
 auto b2 = Box!(double, 3, 4)();
 b1.Fun(b2);

 I think the technical name for this is template template parameter.
 Using the above I'm able to do what I need to do, but is there a
 better way?
 and should I use alias or enum?

Template template parameter means exactly that: a template parameter is 
itself a template. See ContainerType below:

struct SomeContainer(T)
{
     T[] elements;
}

struct SomeOtherContainer(T)
{
     struct List(T)
     {}

     // e.g. this one may use a linked list
     List!T elements;
}

struct Foo(alias ContainerType, T)
{
     // Instantiate the 'template template parameter'
     ContainerType!T member;
}

void main()
{
     Foo!(SomeContainer, double) foo1;
     Foo!(SomeOtherContainer, int) foo2;
}

ContainerType is a template parameter of Foo and is itself a template.

And 'alias' seems to work...

Ali

Caligo <iteronvexor gmail.com> writes:

I should have been more clear, but my actual question is how do I
access the parameters of a template parameter.  My example works, but
I wanted to know if there is a different and perhaps a better of doing
it.

In your example it would look something like this:

struct SomeContainer(T, int x, int y){     }

struct Foo(alias ContainerType){

  // e.g.
  int my_x = ContainerType.x * 2;
  int my_y = ContainerType.y * 2;
}

=?ISO-8859-1?Q?Ali_=C7ehreli?= <acehreli yahoo.com> writes:

On 03/30/2011 04:32 PM, Caligo wrote:
 I have a struct that looks something like this:

 struct Box(T, size_t width, size_t height){

 alias width width_;
 alias height height_;

 //do something with a Box of different size
    void Fun( B )(B b){
      // using width and height of b
      B.width_;
      B.height_;
    }
 }

 auto b1 = Box!(double, 2, 7)();
 auto b2 = Box!(double, 3, 4)();
 b1.Fun(b2);

 I think the technical name for this is template template parameter.
 Using the above I'm able to do what I need to do, but is there a
 better way?
 and should I use alias or enum?

You later also said:

 how do I access the parameters of a template parameter

With the help of function template parameter deduction, I was able to do 
it by spelling out the parameters of Fun:

import std.stdio;

struct Box(T, int width, int height)
{
     void Fun(T2, int width2, int height2)(Box!(T2, width2, height2) b)
     {
         writeln(width2, ' ', height2);
     }
}

void main()
{
     auto b1 = Box!(double, 2, 7)();
     auto b2 = Box!(double, 3, 4)();
     b1.Fun(b2);
}

Ali