digitalmars.D.learn - template evaluation
Hi all,
I must overlook something, but
given this:
´´´
void main(){}
static assert(isMatching!(D, S!(D, true))); // place 1: works as
expected.
struct D
{
auto static s = S!(typeof(this), true).init;
}
enum bool isMatching(T, U) =
(){
bool b;
static foreach(i, m; __traits(allMembers, T))
{
static if(is(typeof(__traits(getMember, T, m)) ==
U))
{
if(b) return false;
else b = true;
}
}
return b;
}();
struct S(T, bool c = false)
//if(isMatching!(T, S!(T, true))) // place 2: does not work
{}
´´´
While "place 1" works as expected: it static asserts to true, if
type D has a single coinciding member to the checked one and
static asserts to false if it doesn't or if there are more of
them then one;
Why I can't use the same template in "place 2"?
PS: Taken the (){}() pattern from here:
https://p0nce.github.io/d-idioms/#Precomputed-tables-at-compile-time-through-CTFE
Apr 14 2018
Ok, trying to reduce my example a little bit, I arrived at this:
´´´
void main(){}
struct D
{
size_t dummy;
auto static s = S!D.init;
}
struct S(alias container = null)
{
pragma(msg, container);
static if(__traits(compiles, __traits(allMembers, container)))
{
static foreach(m; __traits(allMembers, container))
{
pragma(msg, m);
pragma(msg, is(typeof(__traits(getMember, container, m))));
/*
for D.dummy this yields "true"
for D.s this yields "false"
*/
}
}
}
´´´
What I clearly have, is a circular reference, now I'm aware of
this.
So, am I trying something illegal? It seems, I can't get the type
of the according member of the template parameter, even then (or
should I say "especially because") the analyzing type has the
same type.
But if this would be the only member, which I can't get the type
of, the information would be enough, to ensure what I want. Is it
like this?
Apr 14 2018








Alex <sascha.orlov gmail.com>