• Uplink_Coder (5/5) Nov 13 2013 sort doesn't work on an primitive Array ?
• bearophile (6/11) Nov 13 2013 One way to solve your char[]:
• Namespace (2/14) Nov 13 2013 How intuitive. :D
• Jonathan M Davis (6/17) Nov 13 2013 And why not just return the original and avoid the cast? sort sorts in p...
• Andrea Fontana (15/20) Nov 13 2013 By the way:
• bearophile (4/6) Nov 13 2013 That's deprecated (or going to be).
• Chris Cain (11/12) Nov 13 2013 Basically, char[] is a (mutable) string. Since strings in D are
• Uplink_Coder (5/5) Nov 13 2013 I don't want to have a string
• Jonathan M Davis (15/21) Nov 13 2013 Strings are treated as ranges of dchar, so if the element types is char ...

"Uplink_Coder" <someemail someprovider.some> writes:

sort doesn't work on an primitive Array ?
Is that normal ....
please look  http://www.dpaste.dzfl.pl/961286e1
because I don't know what i'm doing worng

Thanks in Advance :D

"bearophile" <bearophileHUGS lycos.com> writes:

Uplink_Coder:

 sort doesn't work on an primitive Array ?
 Is that normal ....
 please look  http://www.dpaste.dzfl.pl/961286e1
 because I don't know what i'm doing worng

 Thanks in Advance :D

One way to solve your char[]:

return cast(typeof(vars))vars.representation.sort().release;


representation is in std.string.

Bye,
bearophile

"Namespace" <rswhite4 googlemail.com> writes:

On Wednesday, 13 November 2013 at 10:58:02 UTC, bearophile wrote:
 Uplink_Coder:

 sort doesn't work on an primitive Array ?
 Is that normal ....
 please look  http://www.dpaste.dzfl.pl/961286e1
 because I don't know what i'm doing worng

 Thanks in Advance :D

 One way to solve your char[]:

 return cast(typeof(vars))vars.representation.sort().release;


 representation is in std.string.

 Bye,
 bearophile

How intuitive. :D

Jonathan M Davis <jmdavisProg gmx.com> writes:

On Wednesday, November 13, 2013 11:58:01 bearophile wrote:
 Uplink_Coder:
 sort doesn't work on an primitive Array ?
 Is that normal ....
 please look  http://www.dpaste.dzfl.pl/961286e1
 because I don't know what i'm doing worng
 
 Thanks in Advance :D

 
 One way to solve your char[]:
 
 return cast(typeof(vars))vars.representation.sort().release;

And why not just return the original and avoid the cast? sort sorts in place. 
e.g.

sort(vars.representation());
return vars;

- Jonathan M Davis

"Andrea Fontana" <nospam example.com> writes:

On Wednesday, 13 November 2013 at 10:32:19 UTC, Uplink_Coder 
wrote:
 sort doesn't work on an primitive Array ?
 Is that normal ....
 please look  http://www.dpaste.dzfl.pl/961286e1
 because I don't know what i'm doing worng

 Thanks in Advance :D

By the way:

return sort(vars); //sort return a range i think, not a char[];

Maybe you want to do:

return vars.sort;  // (not sort in std.algorithms)

or:

import std.array;
...

auto getAllVariables (Pair[][] parsedSysten)  // Auto instead of 
char[]
...
...
return sort(vars.array);  // vars.array


I'm not sure why sort(vars) doesn't work...

"bearophile" <bearophileHUGS lycos.com> writes:

Andrea Fontana:

 Maybe you want to do:

 return vars.sort;  // (not sort in std.algorithms)

That's deprecated (or going to be).

Bye,
bearophile

"Chris Cain" <clcain uncg.edu> writes:

On Wednesday, 13 November 2013 at 11:03:40 UTC, Andrea Fontana 
wrote:
 I'm not sure why sort(vars) doesn't work...

Basically, char[] is a (mutable) string. Since strings in D are 
treated as UTF, hasLength!(char[]) is actually false. Each 
"character" can actually be multiple bytes long, so it sort of 
makes sense. If you were to allow sorting of strings, then 
characters would be broken apart in the sorting process... so it 
doesn't do what you would expect it to do in those cases.

So, the way around it is to just treat it as numbers (using 
std.string.representation, as bearophile pointed out) and sort it 
that way.

"Uplink_Coder" <someemail someprovider.some> writes:

I don't want to have a string
but an array of letters maybe I justgo with ubyte
....
Solved it :D

return cast(char[])sort(cast(ubyte[])vars).release;

Jonathan M Davis <jmdavisProg gmx.com> writes:

On Wednesday, November 13, 2013 11:32:18 Uplink_Coder wrote:
 sort doesn't work on an primitive Array ?
 Is that normal ....
 please look  http://www.dpaste.dzfl.pl/961286e1
 because I don't know what i'm doing worng
 
 Thanks in Advance :D

Strings are treated as ranges of dchar, so if the element types is char or 
wchar, they're not random-access (since the number of code units per code 
point varies, meaning that each element in the array is a piece of a character 
and not necessarily an entire character), and sort requires random access. So, 
if you want to properly sort the string, you need to convert it to a random-
access range - the mostly likely choice being dchar[], which you could do with 
to!(dchar[])(charArray), but of course, if you then want char[] again, you'd 
need to convert it back, e.g. to!(char[])(sort(to!(dchar[])(charArray))).

However, if you're _certain_ that all of the characters are ASCII and 
therefore don't take more than one char, you can convert the string to ubyte[] 
and sort that. std.string.representation will do that for you. e.g. 
sort(representation(charArray)). But that _will_ mangle Unicode strings, so 
you need to be sure that your string only contains ASCII characters.

- Jonathan M Davis