• yawniek (9/9) Nov 22 2015 hi!
• Rikki Cattermole (21/28) Nov 22 2015 I take it that browscap[0] does it not do what you want?
• yawniek (17/32) Nov 23 2015 Hi Rikki,
• Rikki Cattermole (16/47) Nov 23 2015 So like this?

yawniek <dlang srtnwz.com> writes:

hi!

how can i format  a string with captures from a regular 
expression?
basically make this pass:
https://gist.github.com/f17647fb2f8ff2261d42


context: i'm trying to write a implementation for 
https://github.com/ua-parser
where the regular expression as well as the format strings are 
given.

Rikki Cattermole <alphaglosined gmail.com> writes:

On 23/11/15 12:41 PM, yawniek wrote:
 hi!

 how can i format  a string with captures from a regular expression?
 basically make this pass:
 https://gist.github.com/f17647fb2f8ff2261d42


 context: i'm trying to write a implementation for
 https://github.com/ua-parser
 where the regular expression as well as the format strings are given.

I take it that browscap[0] does it not do what you want?
I have an generator at [1].
Feel free to steal.

Also once you do get yours working, you'll want to use ctRegex and 
generate a file with all of them in it. That'll increase performance 
significantly.

Reguarding regex, if you want a named sub part use:
(?<text>[a-z]*)
Where [a-z]* is just an example.

I would recommend you learning how input ranges work. They are used with 
how to get the matches out, e.g.

auto rgx = ctRegex!`([a-z])[123]`;
foreach(match; rgx.matchAll("b3")) {
     writeln(match.hit);
}

Or something along those lines, I did it off the top of my head.

[0] 
https://github.com/rikkimax/Cmsed/blob/master/tools/browser_detection/browscap.ini
[1] 
https://github.com/rikkimax/Cmsed/blob/master/tools/browser_detection/generator.d

yawniek <dlang srtnwz.com> writes:

Hi Rikki,

On Monday, 23 November 2015 at 03:57:06 UTC, Rikki Cattermole 
wrote:
 I take it that browscap[0] does it not do what you want?
 I have an generator at [1].
 Feel free to steal.

This looks interesting, thanks for the hint. However it might be 
a bit limited,
i have 15M+ different User Agents with all kind of weird cases, 
sometimes not even the extensive ua-core regexs work. (if you're 
interested for testing let me know)

 Also once you do get yours working, you'll want to use ctRegex 
 and generate a file with all of them in it. That'll increase 
 performance significantly.

that was my plan.

 Reguarding regex, if you want a named sub part use:
 (?<text>[a-z]*)
 Where [a-z]* is just an example.

 I would recommend you learning how input ranges work. They are 
 used with how to get the matches out, e.g.

 auto rgx = ctRegex!`([a-z])[123]`;
 foreach(match; rgx.matchAll("b3")) {
     writeln(match.hit);
 }

i'm aware how this works, the problem is a different  one:

i do have a second string that contains $n's which can occur in 
any order.
now of course i can just go and write another regex and replace 
it, job done.
but from looking at std.regex this seems to be built in, i just 
failed to get it to work properly, see my gist. i hoped this to 
be a 1liner.

Rikki Cattermole <alphaglosined gmail.com> writes:

On 23/11/15 9:22 PM, yawniek wrote:
 Hi Rikki,

 On Monday, 23 November 2015 at 03:57:06 UTC, Rikki Cattermole wrote:
 I take it that browscap[0] does it not do what you want?
 I have an generator at [1].
 Feel free to steal.

 This looks interesting, thanks for the hint. However it might be a bit
 limited,
 i have 15M+ different User Agents with all kind of weird cases,
 sometimes not even the extensive ua-core regexs work. (if you're
 interested for testing let me know)

 Also once you do get yours working, you'll want to use ctRegex and
 generate a file with all of them in it. That'll increase performance
 significantly.

 that was my plan.

 Reguarding regex, if you want a named sub part use:
 (?<text>[a-z]*)
 Where [a-z]* is just an example.

 I would recommend you learning how input ranges work. They are used
 with how to get the matches out, e.g.

 auto rgx = ctRegex!`([a-z])[123]`;
 foreach(match; rgx.matchAll("b3")) {
     writeln(match.hit);
 }

 i'm aware how this works, the problem is a different  one:

 i do have a second string that contains $n's which can occur in any order.
 now of course i can just go and write another regex and replace it, job
 done.
 but from looking at std.regex this seems to be built in, i just failed
 to get it to work properly, see my gist. i hoped this to be a 1liner.

So like this?

import std.regex;
import std.stdio : readln, writeln, write, stdout;

auto REG = ctRegex!(`(\S+)(?: (.*))?`);

void main() {
         for(;;) {
                 write("> ");
                 stdout.flush;
                 string line = readln();
                 line.length--;

                 if (line.length == 0)
                         return;

                 writeln("< ", line.replaceAll(REG, "Unknown program: $1"));
         }
}