• xtimoner (7/7) Apr 28 2014 synchronized class EventLog{
• =?UTF-8?B?QWxpIMOHZWhyZWxp?= (16/23) Apr 28 2014 Only if there is only one EventLog object. A synchronized class means

"xtimoner" <xtimoner gmail.com> writes:

synchronized class EventLog{
     void opCall(string s){
         std.file.append("logfile.txt", s);
     }
}

shared EventLog eventLog;

Pleas, is it multithread safe and prefered way?

=?UTF-8?B?QWxpIMOHZWhyZWxp?= <acehreli yahoo.com> writes:

On 04/28/2014 01:16 PM, xtimoner wrote:

 synchronized class EventLog{
      void opCall(string s){
          std.file.append("logfile.txt", s);
      }
 }

 shared EventLog eventLog;

 Pleas, is it multithread safe and prefered way?

Only if there is only one EventLog object. A synchronized class means 
that there can be only one member function executed on the same object 
at a given time. Your code is the equivalent of the following:

class EventLog{
     void opCall(string s){
         synchronized (this) {    // <-- NOTE (this)
             std.file.append("logfile.txt", s);
         }
     }
}

So, opCall (and other member functions) is synchronized on a particular 
object.

If you have more than one EventLog, then they can write to the same file 
at the same time and that would be a problem.

Ali