• Steven Schveighoffer (14/14) Jun 10 2016 Consider:
• ArturG (6/21) Jun 10 2016 i guess thats the same reason that

Steven Schveighoffer <schveiguy yahoo.com> writes:

Consider:

import std.traits;
class Foo
{
    void bar() {}
    void baz()() {}
}

This works:

static assert(isCallable!(Foo.bar));

This does not:

static assert(isCallable!(Foo.baz));

However, clearly I can call baz due to IFTI (with the equivalent syntax, 
someFoo.baz() or someFoo.baz). Is there a way to fix this?

-Steve

ArturG <var.spool.mail700 gmail.com> writes:

On Friday, 10 June 2016 at 17:32:03 UTC, Steven Schveighoffer 
wrote:
 Consider:

 import std.traits;
 class Foo
 {
    void bar() {}
    void baz()() {}
 }

 This works:

 static assert(isCallable!(Foo.bar));

 This does not:

 static assert(isCallable!(Foo.baz));

 However, clearly I can call baz due to IFTI (with the 
 equivalent syntax, someFoo.baz() or someFoo.baz). Is there a 
 way to fix this?

 -Steve

i guess thats the same reason that

isCallable!(unaryFun!someString) -> false

if not, then it probably would also be usefull if it would be 
evaluated to true.