• Johnson Jones (20/20) Aug 20 2017 cannot access frame of function

Johnson Jones <JJ Dynomite.com> writes:

cannot access frame of function

I declared a helper function outside a lambda that is passed to C.

The semantics are the same inside of the function as they are 
outside as far as code goes.

How can I declare a function that essentially works inside the 
lambda also without having to do any real rewriting?

e.g., if I could use a define

#define foo(a,b) a + b


would work great, that is all I really need, templates have the 
same issue as functions though.

To make it work I used a mixin template, but that seems a bit 
obtuse ;/

e.g.,

template put()
{
     int foo(a,b) { return a + b; }
}

mixin put;


then I mixin it inside the lambda also. That way I have both 
contexts covered, not bad but...