• Lloyd Dupont (3/3) Jun 12 2011 Apparently std.string.format() is not implemented / does not compile! :(
• bearophile (10/11) Jun 12 2011 This works for me, DMD 2.053:
• Lloyd Dupont (5/6) Jun 12 2011 mm... ok.
• David Nadlinger (4/7) Jun 12 2011 Because format presumably can't be interpreted at compile time (yet) –...
• Jonathan M Davis (14/22) Jun 12 2011 Yeah. format can only be used at runtime. If you want a version which wo...
• Lloyd Dupont (15/22) Jun 12 2011 yep, the example is simple because it is an example!
• jdrewsen (6/9) Jun 12 2011 Because the mixin is evaluated at compile time. This means that

"Lloyd Dupont" <ld-REMOVE galador.net> writes:

Apparently std.string.format() is not implemented / does not compile! :(
Is there any sort of replacement?
Something which works like writefln() but output a string!

bearophile <bearophileHUGS lycos.com> writes:

Lloyd Dupon:

 Apparently std.string.format() is not implemented / does not compile! :(

This works for me, DMD 2.053:

import std.stdio, std.string;

void main() {
    int x = 10;
    auto s = format("%d", 10);
    writeln(">", s, "<");
}


Bye,
bearophile

"Lloyd Dupont" <ld-REMOVE galador.net> writes:

mm... ok.
but why the line below doesn't compile?

mixin(format("class %s {}", "A"));



"bearophile"  wrote in message news:it2pf5$1qh6$1 digitalmars.com... 
 Apparently std.string.format() is not implemented / does not compile! :(

This works for me, DMD 2.053:

David Nadlinger <see klickverbot.at> writes:

On 6/12/11 6:37 PM, Lloyd Dupont wrote:
 mm... ok.
 but why the line below doesn't compile?

 mixin(format("class %s {}", "A"));

Because format presumably can't be interpreted at compile time (yet) – 
not all functions are necessarily CTFEable.

David

Jonathan M Davis <jmdavisProg gmx.com> writes:

On 2011-06-12 10:30, David Nadlinger wrote:
 On 6/12/11 6:37 PM, Lloyd Dupont wrote:
 mm... ok.
 but why the line below doesn't compile?
=20
 mixin(format("class %s {}", "A"));

=20
 Because format presumably can't be interpreted at compile time (yet) =E2=

=80=93
 not all functions are necessarily CTFEable.

Yeah. format can only be used at runtime. If you want a version which works=
 at=20
compile time, then you std.metastrings.Format, which is an eponymous templa=
te.=20
e.g.

mixin(Format!("class %s {}", "A"));

should work. Of course, in this particular case, you might as well just giv=
e=20
the whole string to the mixin directly, but I assume that the example is so=
=20
simple simply because it's an example.

=2D Jonathan M Davis

"Lloyd Dupont" <ld-REMOVE galador.net> writes:

yep, the example is simple because it is an example!
Thanks for your suggestion! :)

"Jonathan M Davis"  wrote in message 
news:mailman.850.1307909499.14074.digitalmars-d-learn puremagic.com...

On 2011-06-12 10:30, David Nadlinger wrote:
 On 6/12/11 6:37 PM, Lloyd Dupont wrote:
 mm... ok.
 but why the line below doesn't compile?

 mixin(format("class %s {}", "A"));

 Because format presumably can't be interpreted at compile time (yet) –
 not all functions are necessarily CTFEable.

Yeah. format can only be used at runtime. If you want a version which works 
at
compile time, then you std.metastrings.Format, which is an eponymous 
template.
e.g.

mixin(Format!("class %s {}", "A"));

should work. Of course, in this particular case, you might as well just give
the whole string to the mixin directly, but I assume that the example is so
simple simply because it's an example.

- Jonathan M Davis 

jdrewsen <jdrewsen nospam.com> writes:

Den 12-06-2011 18:37, Lloyd Dupont skrev:
 mm... ok.
 but why the line below doesn't compile?

 mixin(format("class %s {}", "A"));

Because the mixin is evaluated at compile time. This means that 
format(...) is evaluated at compile time which afaik is not supported.

It may be supported in the future with the improved CTFE that is being 
worked on.

/Jonas