• Johan Granberg (19/19) Mar 10 2007 Is this code supposed to work?
• Sean Kelly (6/20) Mar 10 2007 This is because you want foreach to implicitly convert your char array
• Johan Granberg (2/25) Mar 10 2007 Ok, it would be usefull if it worked thou.

Johan Granberg <lijat.meREM OVE.gmail.com> writes:

Is this code supposed to work?

char[] test(char[] d)
{
        char[] v="";
        foreach(dchar c;d)
                v~=c;
        return v;
}
void main()
{
        const a=test("test");
        printf("%*.s",a);
}

I just get this error but I'm unsure if it is a bug or a limitation.

johan Cyclop:~/Desktop$ gdc -o test ctforeach.d 
ctforeach.d:5: Error: cannot evaluate _aApplycd1(d,__foreachbody1) at
compile time
ctforeach.d:11: Error: cannot evaluate test("test") at compile time
johan Cyclop:~/Desktop$ 

Sean Kelly <sean f4.ca> writes:

Johan Granberg wrote:
 Is this code supposed to work?
 
 char[] test(char[] d)
 {
         char[] v="";
         foreach(dchar c;d)
                 v~=c;
         return v;
 }
 void main()
 {
         const a=test("test");
         printf("%*.s",a);
 }

This is because you want foreach to implicitly convert your char array 
to dchars, and this happens in the compier runtime at, well, run-time. 
I imagine it would be possible to create compile-time routines to do 
this, but that feature isn't built into the compiler right now.


Sean

Johan Granberg <lijat.meREM OVE.gmail.com> writes:

Sean Kelly wrote:

 Johan Granberg wrote:
 Is this code supposed to work?
 
 char[] test(char[] d)
 {
         char[] v="";
         foreach(dchar c;d)
                 v~=c;
         return v;
 }
 void main()
 {
         const a=test("test");
         printf("%*.s",a);
 }

 
 This is because you want foreach to implicitly convert your char array
 to dchars, and this happens in the compier runtime at, well, run-time.
 I imagine it would be possible to create compile-time routines to do
 this, but that feature isn't built into the compiler right now.
 
 
 Sean

Ok, it would be usefull if it worked thou.