digitalmars.D.learn - exponent operator/library function
- Michael P. (3/3) Aug 04 2008 Quick question: What do you have to use to do something like, 10 to the ...
- BCS (2/9) Aug 04 2008 iirc its.math.pow(base,exp);
- Michael P. (8/21) Aug 04 2008 Unfortunately, those didn't work( because of type issues). So I made my ...
- BCS (5/8) Aug 04 2008 line 125: for ( int i = arrayToConvert.length; i > 0; i-- )
- Jarrett Billingsley (6/14) Aug 04 2008 You mean i >= 0, I suppose. ;)
- BCS (10/33) Aug 04 2008 Keep (gently) needling me on that. I need to do better.
- Jarrett Billingsley (11/17) Aug 04 2008 cast(int)std.math.pow(10, j)
- Michael P. (5/30) Aug 05 2008 Oh. I just thought it dynamically allocated memory for each new element.
Quick question: What do you have to use to do something like, 10 to the power of 3? Something in std.math, a built-in operator? That's all. -Michael P.
Aug 04 2008
Reply to Michael P.,Quick question: What do you have to use to do something like, 10 to the power of 3? Something in std.math, a built-in operator? That's all. -Michael P.iirc its.math.pow(base,exp);
Aug 04 2008
BCS Wrote:Reply to Michael P.,Unfortunately, those didn't work( because of type issues). So I made my own integer one. :) Anyways, somewhat unrelated question: I have attached a file that includes a simple program that I've made for keeping the brain fit, with memory. I've also made one that let's you do simple addition. :D Anyways, everything is compiling fine, but I get an ArrayOutOfBounds error on line 125 or something. Okay, it's function createArray, which is called by memoryTest. Line 114, 115. The file is attached. Does anyone know I'm getting these array errors? -Michael P.Quick question: What do you have to use to do something like, 10 to the power of 3? Something in std.math, a built-in operator? That's all. -Michael P.iirc its.math.pow(base,exp);
Aug 04 2008
Reply to Michael P.,Anyways, everything is compiling fine, but I get an ArrayOutOfBounds error on line 125 or something.line 125: for ( int i = arrayToConvert.length; i > 0; i-- ) that should be: for ( int i = arrayToConvert.length - 1; i > 0; i-- ) this is because arr[arr.length] is the elemant after the last element.
Aug 04 2008
"BCS" <ao pathlink.com> wrote in message news:55391cb32ff418cac458bee9a3c8 news.digitalmars.com...Reply to Michael P.,You mean i >= 0, I suppose. ;)Anyways, everything is compiling fine, but I get an ArrayOutOfBounds error on line 125 or something.line 125: for ( int i = arrayToConvert.length; i > 0; i-- ) that should be: for ( int i = arrayToConvert.length - 1; i > 0; i-- )this is because arr[arr.length] is the elemant after the last element.No offense BCS, but for someone so well-spoken and intelligent, I'm kind of shocked at how poor/inconsistent your spelling is. "elemant" and "element" in the same sentence?
Aug 04 2008
Reply to Jarrett,"BCS" <ao pathlink.com> wrote in message news:55391cb32ff418cac458bee9a3c8 news.digitalmars.com...that as wellReply to Michael P.,You mean i >= 0, I suppose. ;)Anyways, everything is compiling fine, but I get an ArrayOutOfBounds error on line 125 or something.line 125: for ( int i = arrayToConvert.length; i > 0; i-- ) that should be: for ( int i = arrayToConvert.length - 1; i > 0; i-- )Keep (gently) needling me on that. I need to do better. OTOH I have on occasion wondered if I'm borderline dyslexic (My mind just doesn't seem to "see" spelling errors). I've never bothered to get tested so I can't claim it as a reason and even if I did get tested I can't claim it as an excuse*. Really what I need to do is figure out how to get a spell checker plugged into my NG reader :b * there is a fun debate in that fine distinctionthis is because arr[arr.length] is the elemant after the last element.No offense BCS, but for someone so well-spoken and intelligent, I'm kind of shocked at how poor/inconsistent your spelling is. "elemant" and "element" in the same sentence?
Aug 04 2008
"Michael P." <baseball.mjp gmail.com> wrote in message news:g77tc7$2fkr$1 digitalmars.com...Unfortunately, those didn't work( because of type issues). So I made my own integer one. :)cast(int)std.math.pow(10, j) ...Okay, it's function createArray, which is called by memoryTest. Line 114, 115. The file is attached. Does anyone know I'm getting these array errors?int[] memoryList; for ( int i = 0; i < lengthOfList; i++ ) { memoryList[i] = rand() % 10; ... Maaaaybe you can see it now. Hint: how long is memoryList?
Aug 04 2008
Jarrett Billingsley Wrote:"Michael P." <baseball.mjp gmail.com> wrote in message news:g77tc7$2fkr$1 digitalmars.com...Oh. I just thought it dynamically allocated memory for each new element. Anyways, I put memoryList.length = lengthOfList above the for statement. Anyways, thanks for the help. :) -Michael P.Unfortunately, those didn't work( because of type issues). So I made my own integer one. :)cast(int)std.math.pow(10, j)Okay, it's function createArray, which is called by memoryTest. Line 114, 115. The file is attached. Does anyone know I'm getting these array errors?int[] memoryList; for ( int i = 0; i < lengthOfList; i++ ) { memoryList[i] = rand() % 10; ... Maaaaybe you can see it now. Hint: how long is memoryList?
Aug 05 2008