digitalmars.D.learn - convert string to ubyte[]
- aki (15/15) Nov 11 2017 Hello,
- Guillaume Piolat (9/24) Nov 11 2017 to!(ubyte[]) is a semantic transformation that tries to parse an
- Mike Parker (13/28) Nov 11 2017 I don't know about the error you're seeing, but the generic way
Hello, This will be trivial question but I cannot figure out what's wrong. I want to convert string to an array of ubyte. import std.conv; void main() { auto s = "hello"; ubyte[] b = to!(ubyte[])(s); } It compiles but cause run time error: std.conv.ConvException C:\APP\D\dmd2\windows\bin\..\..\src\phob s\std\conv.d(3530): Can't parse string: "[" is missing I cannot understand the meaning of this message. Replacing s with s.dup to remove immutable doesn't help. Do I need to use cast? Regards, Aki
Nov 11 2017
On Saturday, 11 November 2017 at 15:38:18 UTC, aki wrote:Hello, This will be trivial question but I cannot figure out what's wrong. I want to convert string to an array of ubyte. import std.conv; void main() { auto s = "hello"; ubyte[] b = to!(ubyte[])(s); } It compiles but cause run time error: std.conv.ConvException C:\APP\D\dmd2\windows\bin\..\..\src\phob s\std\conv.d(3530): Can't parse string: "[" is missing I cannot understand the meaning of this message. Replacing s with s.dup to remove immutable doesn't help. Do I need to use cast? Regards, Akito!(ubyte[]) is a semantic transformation that tries to parse an array literal it seems. You can use slice casting instead: import std.conv; void main() { auto s = "hello"; ubyte[] b = cast(ubyte[])(s.dup); }
Nov 11 2017
On Saturday, 11 November 2017 at 15:38:18 UTC, aki wrote:Hello, This will be trivial question but I cannot figure out what's wrong. I want to convert string to an array of ubyte. import std.conv; void main() { auto s = "hello"; ubyte[] b = to!(ubyte[])(s); } It compiles but cause run time error: std.conv.ConvException C:\APP\D\dmd2\windows\bin\..\..\src\phob s\std\conv.d(3530): Can't parse string: "[" is missing I cannot understand the meaning of this message. Replacing s with s.dup to remove immutable doesn't help. Do I need to use cast? Regards, AkiI don't know about the error you're seeing, but the generic way to get an array of the underlying data type of a string is via std.string.representation. import std.string; auto s = "hello"; auto bytes = s.representation; https://dlang.org/phobos/std_string.html#.representation You can also simply cast to the appropriate type if you already know what type of string you have. auto bytes = cast(immutable(ubyte)[])s; Of course, if you need a mutable array you should dup: auto bytes = cast(ubyte[])s.dup;
Nov 11 2017
On Saturday, 11 November 2017 at 15:48:59 UTC, Mike Parker wrote:On Saturday, 11 November 2017 at 15:38:18 UTC, aki wrote: auto bytes = cast(immutable(ubyte)[])s; Of course, if you need a mutable array you should dup: auto bytes = cast(ubyte[])s.dup;Not only "should" but he "must" otherwise with string literals he'll get a violation access error.
Nov 11 2017
On Saturday, 11 November 2017 at 15:48:59 UTC, Mike Parker wrote:On Saturday, 11 November 2017 at 15:38:18 UTC, aki wrote:That function needs to be highlighted more through documentation. I've always implemented my own versions to achieve the same as representation. I had no idea that function existed. If just I knew.[...]I don't know about the error you're seeing, but the generic way to get an array of the underlying data type of a string is via std.string.representation. import std.string; auto s = "hello"; auto bytes = s.representation; https://dlang.org/phobos/std_string.html#.representation You can also simply cast to the appropriate type if you already know what type of string you have. auto bytes = cast(immutable(ubyte)[])s; Of course, if you need a mutable array you should dup: auto bytes = cast(ubyte[])s.dup;
Nov 11 2017
On Saturday, 11 November 2017 at 15:48:59 UTC, Mike Parker wrote:auto s = "hello"; auto bytes = s.representation; https://dlang.org/phobos/std_string.html#.representationThank you for the replay. Now I know. aki
Nov 11 2017