• Warwick (5/5) Jan 15 2016 I though C style casts were not supported? But when I accidentaly
• Ilya Yaroshenko (4/9) Jan 15 2016 This is not a cast. You call constructor `uint(int x)`.
• Jacob Carlborg (7/11) Jan 15 2016 Wouldn't a C style cast be:
• Warwick (2/13) Jan 16 2016 Yeah bad memory on my part, it's C++ cast, or one of them.

Warwick <warwick warwick.com> writes:

I though C style casts were not supported? But when I accidentaly 
did

int i;
if (uint(i) < length) ....

it compiled and worked fine. Whys that?

Ilya Yaroshenko <ilyayaroshenko gmail.com> writes:

On Friday, 15 January 2016 at 10:16:41 UTC, Warwick wrote:
 I though C style casts were not supported? But when I 
 accidentaly did

 int i;
 if (uint(i) < length) ....

 it compiled and worked fine. Whys that?

This is not a cast. You call constructor `uint(int x)`.
In the same time `uint(somethingTypeOfLong)` would not work, but 
cast(long). --Ilya

Jacob Carlborg <doob me.com> writes:

On 2016-01-15 11:16, Warwick wrote:
 I though C style casts were not supported? But when I accidentaly did

 int i;
 if (uint(i) < length) ....

 it compiled and worked fine. Whys that?

Wouldn't a C style cast be:

int i;
if ((uint)i < length)

?

-- 
/Jacob Carlborg

Warwick <warwick warwick.com> writes:

On Friday, 15 January 2016 at 15:13:37 UTC, Jacob Carlborg wrote:
 On 2016-01-15 11:16, Warwick wrote:
 I though C style casts were not supported? But when I 
 accidentaly did

 int i;
 if (uint(i) < length) ....

 it compiled and worked fine. Whys that?

 Wouldn't a C style cast be:

 int i;
 if ((uint)i < length)

Yeah bad memory on my part, it's C++ cast, or one of them.