digitalmars.D.learn - Why isn't intended class constructor called?
- Zak (35/35) Jan 28 2019 I have defined a class that's meant to represent a data series,
I have defined a class that's meant to represent a data series, which has an index and a set of values. Sometimes the user wants to specify a particular index of custom type, other times they don't care and we want to default to an array of contiguous "int" starting from 0. I have attempted to create a class where the index type is a parameter, but defaults to int. I also tried to create two constructors: one for if the index values are not specified (in which the constructor makes the array of ints); and one where the user passes in a literal of values that match the specified type. However, it seems that only the first constructor is getting called, even though I am passing in two parameters instead of one. Why isn't the call matching the second constructor and behaving as intended? import std.stdio; class MyClass(T, U = int) { T[] values; U[] index; this(T[] values) { this.values = values; // Default index of contiguous ints for (int i; i < values.length; i++) { index ~= i; } } this(T[] values, U[] index) { this.values = values; this.index = index; } } void main() { auto myc1 = new MyClass!(int)([1,2,-3]); auto myc2 = new MyClass!(int, string)([1,2,-3], ["a", "b", "c"]); // Error: cannot append type int to type string[] }
Jan 28 2019
On Monday, 28 January 2019 at 18:34:44 UTC, Zak wrote:I have defined a class that's meant to represent a data series, which has an index and a set of values. Sometimes the user wants to specify a particular index of custom type, other times they don't care and we want to default to an array of contiguous "int" starting from 0. I have attempted to create a class where the index type is a parameter, but defaults to int. I also tried to create two constructors: one for if the index values are not specified (in which the constructor makes the array of ints); and one where the user passes in a literal of values that match the specified type. However, it seems that only the first constructor is getting called, even though I am passing in two parameters instead of one. Why isn't the call matching the second constructor and behaving as intended? import std.stdio; class MyClass(T, U = int) { T[] values; U[] index; this(T[] values) { this.values = values; // Default index of contiguous ints for (int i; i < values.length; i++) { index ~= i; } } this(T[] values, U[] index) { this.values = values; this.index = index; } } void main() { auto myc1 = new MyClass!(int)([1,2,-3]); auto myc2 = new MyClass!(int, string)([1,2,-3], ["a", "b", "c"]); // Error: cannot append type int to type string[] }As the error states: you are trying to append an int to a string array in the single parameter constructor. This would work: ´´´ import std.stdio; class MyClass(T, U = int) { T[] values; U[] index; this(T[] values) { this.values = values; // Default index of contiguous ints static if(is(U == int)) { for (int i; i < values.length; i++) { index ~= i; } } } this(T[] values, U[] index) { this.values = values; this.index = index; } } void main() { auto myc1 = new MyClass!(int)([1,2,-3]); auto myc2 = new MyClass!(int, string)([1,2,-3], ["a", "b", "c"]); // Error: cannot append type int to type string[] } ´´´ If design matters, I would even to expand the static if above the constructor. So, the single parameter constructor would exist iff is(U == int) ´´´ static if(is(U == int)) { this(T[] values) { this.values = values; // Default index of contiguous ints for (int i; i < values.length; i++) { index ~= i; } } } ´´´
Jan 28 2019
On Monday, 28 January 2019 at 18:50:18 UTC, Alex wrote:On Monday, 28 January 2019 at 18:34:44 UTC, Zak wrote:Thanks for the response, Alex! But it's not clear to me why the first constructor is called at all. Since I called with two parameters, shouldn't it invoke the second constructor?[...]As the error states: you are trying to append an int to a string array in the single parameter constructor. [...]
Jan 28 2019
On Monday, 28 January 2019 at 19:15:04 UTC, Zak wrote:On Monday, 28 January 2019 at 18:50:18 UTC, Alex wrote:I think I just realized the answer: this section of code is not called, it just fails compilation since it's not known that runtime doesn't do something like: auto myc = new MyClass!(int, string)([1,2,-3]); which "would" invoke this code block with type string.On Monday, 28 January 2019 at 18:34:44 UTC, Zak wrote:Thanks for the response, Alex! But it's not clear to me why the first constructor is called at all. Since I called with two parameters, shouldn't it invoke the second constructor?[...]As the error states: you are trying to append an int to a string array in the single parameter constructor. [...]
Jan 28 2019
On Monday, 28 January 2019 at 19:24:21 UTC, Zak wrote:On Monday, 28 January 2019 at 19:15:04 UTC, Zak wrote:Yes. :)On Monday, 28 January 2019 at 18:50:18 UTC, Alex wrote:I think I just realized the answer: this section of code is not called, it just fails compilation since it's not known that runtime doesn't do something like: auto myc = new MyClass!(int, string)([1,2,-3]); which "would" invoke this code block with type string.On Monday, 28 January 2019 at 18:34:44 UTC, Zak wrote:Thanks for the response, Alex! But it's not clear to me why the first constructor is called at all. Since I called with two parameters, shouldn't it invoke the second constructor?[...]As the error states: you are trying to append an int to a string array in the single parameter constructor. [...]
Jan 28 2019