• Gary Willoughby (5/5) Mar 19 2014 Why does the following program write the message 'Foo' twice?
• Vladimir Panteleev (8/13) Mar 19 2014 The message is not printed by the program, but by the compiler.
• Gary Willoughby (3/6) Mar 19 2014 Yes i'm using rdmd. Thanks.
• Dicebot (5/10) Mar 19 2014 Once upon compilation and once upon run-time. I don't know if it
• Dicebot (1/1) Mar 19 2014 Disregard my comment, Vladimir is right :)

"Gary Willoughby" <dev nomad.so> writes:

Why does the following program write the message 'Foo' twice?

void main(string[] args)
{
	pragma(msg, "Foo");
}

"Vladimir Panteleev" <vladimir thecybershadow.net> writes:

On Wednesday, 19 March 2014 at 10:08:50 UTC, Gary Willoughby 
wrote:
 Why does the following program write the message 'Foo' twice?

 void main(string[] args)
 {
 	pragma(msg, "Foo");
 }

The message is not printed by the program, but by the compiler.

If you build the program via dmd, the message is only printed 
once.

If you use rdmd, it will be printed twice, because rdmd invokes 
dmd once to gather the program's dependencies, and a second time 
to actually build the program.

"Gary Willoughby" <dev nomad.so> writes:

On Wednesday, 19 March 2014 at 10:10:18 UTC, Vladimir Panteleev 
wrote:
 If you use rdmd, it will be printed twice, because rdmd invokes 
 dmd once to gather the program's dependencies, and a second 
 time to actually build the program.

Yes i'm using rdmd. Thanks.

"Dicebot" <public dicebot.lv> writes:

On Wednesday, 19 March 2014 at 10:08:50 UTC, Gary Willoughby
wrote:
 Why does the following program write the message 'Foo' twice?

 void main(string[] args)
 {
 	pragma(msg, "Foo");
 }

Once upon compilation and once upon run-time. I don't know if it
is intended design but this is how `pragma(msg)` works if put
into function body.

"Dicebot" <public dicebot.lv> writes:

Disregard my comment, Vladimir is right :)