digitalmars.D.learn - What does it mean: buffer[0 .. kSize] = input[index .. (index + Size)];
- t0mek (12/12) Jul 25 2008 Hello,
- Koroskin Denis (7/19) Jul 25 2008 It is *exactly* the same (however, a memcpy could be used under the hood...
- t0mek (3/8) Jul 25 2008 Thanks!
- bearophile (4/5) Jul 25 2008 If compiled in -release mode no exception is thrown, I think.
- BCS (5/27) Jul 25 2008 Not /exaltly/ the same, because IIRC the exception will be thrown before...
Hello, I found some code in D and I am wondering what does it mean: buffer[0 .. Size] = input[index .. (index + Size)]; I understand it can be written like this: for (i=0; i<Size; i++) buffer[i]=input[i+index]; But... 1) does it allocate space for buffer? 2) if buffer has already some data- will be zeroed? 3) if there is no enough date (less then Size) in input will there be an exception or will be copied what already is in the array? Regards, t0mek
Jul 25 2008
On Fri, 25 Jul 2008 12:50:36 +0400, t0mek <t0mek com.com.com.com.com> wrote:Hello, I found some code in D and I am wondering what does it mean: buffer[0 .. Size] = input[index .. (index + Size)]; I understand it can be written like this: for (i=0; i<Size; i++) buffer[i]=input[i+index]; But... 1) does it allocate space for buffer? 2) if buffer has already some data- will be zeroed? 3) if there is no enough date (less then Size) in input will there be an exception or will be copied what already is in the array? Regards, t0mekIt is *exactly* the same (however, a memcpy could be used under the hood), i.e. - there is no allocation - data will be overwritten - an OutOfBounds exception will be thrown if array is not large enough
Jul 25 2008
It is *exactly* the same (however, a memcpy could be used under the hood), i.e. - there is no allocation - data will be overwritten - an OutOfBounds exception will be thrown if array is not large enoughThanks! Regards, t0mek
Jul 25 2008
Koroskin Denis:- an OutOfBounds exception will be thrown if array is not large enoughIf compiled in -release mode no exception is thrown, I think. Bye, bearophile
Jul 25 2008
Reply to Koroskin,On Fri, 25 Jul 2008 12:50:36 +0400, t0mek <t0mek com.com.com.com.com> wrote:Not /exaltly/ the same, because IIRC the exception will be thrown before any copy takes place and the for loop will copy to the end of one of the buffers and then throw. Most of the time the difference isn't important, but...Hello, I found some code in D and I am wondering what does it mean: buffer[0 .. Size] = input[index .. (index + Size)]; I understand it can be written like this: for (i=0; i<Size; i++) buffer[i]=input[i+index]; But... 1) does it allocate space for buffer? 2) if buffer has already some data- will be zeroed? 3) if there is no enough date (less then Size) in input will there be an exception or will be copied what already is in the array? Regards, t0mekIt is *exactly* the same (however, a memcpy could be used under the hood),i.e. - there is no allocation - data will be overwritten - an OutOfBounds exception will be thrown if array is not large enough
Jul 25 2008