digitalmars.D.learn - Using to! ?
Hi, Given the example below: string str = "1 2 3 4 5 6"; double[] numbers = to!(double[])(split(str)); writefln(to!string(numbers)); I get [1, 2, 3, 4, 5, 6] which is okay. How do I output it with different separators? What I would like to get is [ 1 2 3 4 5 6 ] or ( 1 2 3 4 5 6 ). unknown
Jun 17 2009
unknown Wrote:Hi, Given the example below: string str = "1 2 3 4 5 6"; double[] numbers = to!(double[])(split(str)); writefln(to!string(numbers)); I get [1, 2, 3, 4, 5, 6] which is okay. How do I output it with different separators? What I would like to get is [ 1 2 3 4 5 6 ] or ( 1 2 3 4 5 6 ). unknownThis: writeln(std.conv.to!string(numbers, "( ", " ", " )")); Will output: ( 1 2 3 4 5 6 ) And writeln(std.conv.to!string(numbers, "<< ", " | ", " >>")); Will result in: << 1 | 2 | 3 | 4 | 5 | 6 >>
Jun 17 2009
John C Wrote: Thanks John, I already figured it out. There should be an example in the unit tests. Cheers, unknownunknown Wrote:Hi, Given the example below: string str = "1 2 3 4 5 6"; double[] numbers = to!(double[])(split(str)); writefln(to!string(numbers)); I get [1, 2, 3, 4, 5, 6] which is okay. How do I output it with different separators? What I would like to get is [ 1 2 3 4 5 6 ] or ( 1 2 3 4 5 6 ). unknownThis: writeln(std.conv.to!string(numbers, "( ", " ", " )")); Will output: ( 1 2 3 4 5 6 ) And writeln(std.conv.to!string(numbers, "<< ", " | ", " >>")); Will result in: << 1 | 2 | 3 | 4 | 5 | 6 >>
Jun 17 2009
unknown Wrote: Figured it out. Forget it.Hi, Given the example below: string str = "1 2 3 4 5 6"; double[] numbers = to!(double[])(split(str)); writefln(to!string(numbers)); I get [1, 2, 3, 4, 5, 6] which is okay. How do I output it with different separators? What I would like to get is [ 1 2 3 4 5 6 ] or ( 1 2 3 4 5 6 ). unknown
Jun 17 2009