• Jonathan (6/6) Oct 01 2018 I can use `std.traits.getSymbolsByUDA` to get all the members of
• Stanislav Blinov (25/31) Oct 03 2018 You can use .tupleof and hasUDA instead:

Jonathan <JonathanILevi gmail.com> writes:

I can use `std.traits.getSymbolsByUDA` to get all the members of 
a class that have a particular UDA `getSymbolsByUDA(ValueType, 
UDA)`.

But how do I get the values with it?

Is there a more convenient way than `__traits(getMember, value, 
getSymbolsByUDA(ValueType, UDA)[0].stringof)`?

Stanislav Blinov <stanislav.blinov gmail.com> writes:

On Tuesday, 2 October 2018 at 03:30:50 UTC, Jonathan wrote:
 I can use `std.traits.getSymbolsByUDA` to get all the members 
 of a class that have a particular UDA 
 `getSymbolsByUDA(ValueType, UDA)`.

 But how do I get the values with it?

 Is there a more convenient way than `__traits(getMember, value, 
 getSymbolsByUDA(ValueType, UDA)[0].stringof)`?

You can use .tupleof and hasUDA instead:

import std.traits;
import std.stdio;

enum uda1;
enum uda2;

class S {
      uda1 int a = 1;
      uda2 int b = 2;
      uda1 int c = 3;
      uda2 int d = 4;
}

void main() {
     auto s = new S;

     static foreach (i, _; S.tupleof) {
         static if (hasUDA!(_, uda1))
             writefln("uda1 (%s): %s", __traits(identifier, _), 
s.tupleof[i]);
     }

     static foreach (i, _; S.tupleof) {
         static if (hasUDA!(_, uda2))
             writefln("uda2 (%s): %s", __traits(identifier, _), 
s.tupleof[i]);
     }
}