• Simen Haugen (22/22) Apr 19 2007 If I try to call a template when a method with the same name exists I ge...
• Frits van Bommel (5/27) Apr 19 2007 Naming the member function "isInteger" hides the "isInteger" name for
• Simen Haugen (3/30) Apr 19 2007 I though the compiler could see the differance. Thanks.

"Simen Haugen" <simen norstat.no> writes:

If I try to call a template when a method with the same name exists I get a 
compiler error:

template isInteger(T)
{
 static if (is(T == int))
  const bool isInteger = true;
 else
  const bool isInteger = false;
}

class Test
{
 bool isInteger()
 {
  return isInteger!(int); // Yields an compiler error
 }
}

Gives me the error:
test.d(15): template instance isInteger is not a template declaration, it is 
a function

To me it seems this should be legal as my method doesn't take any template 
parameters and the compiler should understand that the template should be 
called.. There must be something I don't understand here... 

Frits van Bommel <fvbommel REMwOVExCAPSs.nl> writes:

Simen Haugen wrote:
 If I try to call a template when a method with the same name exists I get a 
 compiler error:
 
 template isInteger(T)
 {
  static if (is(T == int))
   const bool isInteger = true;
  else
   const bool isInteger = false;
 }
 
 class Test
 {
  bool isInteger()
  {
   return isInteger!(int); // Yields an compiler error
  }
 }
 
 Gives me the error:
 test.d(15): template instance isInteger is not a template declaration, it is 
 a function

Naming the member function "isInteger" hides the "isInteger" name for 
the template while inside the class. The method should "return 
.isInteger!(int);" instead (notice the added '.') to use the global 
isInteger template.

"Simen Haugen" <simen norstat.no> writes:

I though the compiler could see the differance. Thanks.

"Frits van Bommel" <fvbommel REMwOVExCAPSs.nl> wrote in message 
news:f07lk7$29kv$1 digitalmars.com...
 Simen Haugen wrote:
 If I try to call a template when a method with the same name exists I get 
 a compiler error:

 template isInteger(T)
 {
  static if (is(T == int))
   const bool isInteger = true;
  else
   const bool isInteger = false;
 }

 class Test
 {
  bool isInteger()
  {
   return isInteger!(int); // Yields an compiler error
  }
 }

 Gives me the error:
 test.d(15): template instance isInteger is not a template declaration, it 
 is a function

 Naming the member function "isInteger" hides the "isInteger" name for the 
 template while inside the class. The method should "return 
 .isInteger!(int);" instead (notice the added '.') to use the global 
 isInteger template.