• Marek Janukowicz (11/11) Aug 07 2015 How do I mark a function as returning shared object?
• Adam D. Ruppe (8/11) Aug 07 2015 That's correct, though the recommendation now is to put the other
• Steven Schveighoffer (12/21) Aug 07 2015 shared, const, immutable when applied to a member function actually are

Marek Janukowicz <marek janukowicz.net> writes:

How do I mark a function as returning shared object?

This won't compile:

shared Foo foo () {
  ...
}

This does, but looks somewhat awkward to me:

shared (shared Foo) foo () {
  ...
}

-- 
Marek Janukowicz

"Adam D. Ruppe" <destructionator gmail.com> writes:

On Friday, 7 August 2015 at 17:19:16 UTC, Marek Janukowicz wrote:
 shared (shared Foo) foo () {
   ...
 }

That's correct, though the recommendation now is to put the other 
shared on teh right and change the parens a little:

shared(Foo) foo() shared {

}

The ones without parens refer to the `this` in there and are 
kinda confusing to see on the left, so putting them on the right 
looks a bit easier (same with const btw).

Steven Schveighoffer <schveiguy yahoo.com> writes:

On 8/7/15 1:19 PM, Marek Janukowicz wrote:
 How do I mark a function as returning shared object?

 This won't compile:

 shared Foo foo () {
    ...
 }

 This does, but looks somewhat awkward to me:

 shared (shared Foo) foo () {
    ...
 }

shared, const, immutable when applied to a member function actually are 
NOT affecting the return type.

So for instance:

const Foo foo()

Does NOT return a const Foo, but:

const(Foo) foo()

does. The first returns a mutable Foo, and applies const to the 'this' 
parameter for the foo member function (a hidden parameter).

So what you likely want is:

shared(Foo) foo()

-Steve