• Andrej Mitrovic (14/14) Feb 16 2014 -----
• =?UTF-8?B?QWxpIMOHZWhyZWxp?= (7/21) Feb 16 2014 That one uses reals.
• "Casper =?UTF-8?B?RsOmcmdlbWFuZCI=?= <shorttail hotmail.com> (3/3) Feb 16 2014 If you swap the line to

Andrej Mitrovic <andrej.mitrovich gmail.com> writes:

-----
import std.math;
import std.stdio;

void main()
{
    writefln("nextUp of %a is %a", 1.0, 1.0.nextUp());

    real num = 1.0;
    writefln("nextUp of %a is %a", num, num.nextUp());
}
-----

This prints:

nextUp of 0x1p+0 is 0x1.0000000000001p+0
nextUp of 0x1p+0 is 0x1.0000000000000002p+0

Any idea why the results are different?

=?UTF-8?B?QWxpIMOHZWhyZWxp?= <acehreli yahoo.com> writes:

On 02/16/2014 01:42 PM, Andrej Mitrovic wrote:

 -----
 import std.math;
 import std.stdio;

 void main()
 {
      writefln("nextUp of %a is %a", 1.0, 1.0.nextUp());

That line uses doubles.

      real num = 1.0;
      writefln("nextUp of %a is %a", num, num.nextUp());

That one uses reals.

 }
 -----

 This prints:

 nextUp of 0x1p+0 is 0x1.0000000000001p+0
 nextUp of 0x1p+0 is 0x1.0000000000000002p+0

 Any idea why the results are different?

There is no difference. They are both 1. ;)

The type of floating point literals is double. You are seeing the 
precision difference between doubles and reals.

Ali

"Casper =?UTF-8?B?RsOmcmdlbWFuZCI=?= <shorttail hotmail.com> writes:

If you swap the line to
	writefln("nextUp of %a is %a", 1.0L, 1.0L.nextUp());
you get the same result as the second case.