• Dennis Ritchie (12/12) Apr 06 2015 Hi,
• Dennis Ritchie (18/19) Apr 06 2015 Although, perhaps, everything is fine. I just thought that
• Andrea Fontana (7/19) Apr 07 2015 Yes it is.
• Dennis Ritchie (2/9) Apr 07 2015 Thanks. I am aware :)

"Dennis Ritchie" <dennis.ritchie mail.ru> writes:

Hi,
Is it OK?

-----
import std.stdio : writeln;
import std.range : takeNone;

void main() {

	auto s = takeNone("test");

	s ~= 5;

	writeln(s); // prints ♣
}
-----
Windows 8.1 x64, DMD 2.067.0

"Dennis Ritchie" <dennis.ritchie mail.ru> writes:

On Tuesday, 7 April 2015 at 02:24:00 UTC, Dennis Ritchie wrote:
 Is it OK?

Although, perhaps, everything is fine. I just thought that 
creates takeNone not string type string, and the string array of 
type string[].

import std.stdio : writeln;

void main() {

	string s;

	s ~= 5;

	writeln(s); // prints ♣
}

So I mixed up with this case. Everything is OK.

import std.range : takeNone;

void main() {
	
	auto s = takeNone(["test"]);
	
	// s ~= 5; // Error: cannot append type int to type string[]
}

"Andrea Fontana" <mail example.com> writes:

Yes it is.

takeNone() take a char from a string.

So you are going to append a char (with code 5) on the next line.
If you replace that line with:

s ~= 65;

it will print "A".  (65 is ascii code for letter 'A')

On Tuesday, 7 April 2015 at 02:24:00 UTC, Dennis Ritchie wrote:
 Hi,
 Is it OK?

 -----
 import std.stdio : writeln;
 import std.range : takeNone;

 void main() {

 	auto s = takeNone("test");

 	s ~= 5;

 	writeln(s); // prints ♣
 }
 -----
 Windows 8.1 x64, DMD 2.067.0

"Dennis Ritchie" <dennis.ritchie mail.ru> writes:

On Tuesday, 7 April 2015 at 08:49:58 UTC, Andrea Fontana wrote:
 Yes it is.

 takeNone() take a char from a string.

 So you are going to append a char (with code 5) on the next 
 line.
 If you replace that line with:

 s ~= 65;

 it will print "A".  (65 is ascii code for letter 'A')

Thanks. I am aware :)