• Saaa (11/11) Aug 17 2009 const char[] re1 = `(re)1`;
• BCS (3/14) Aug 18 2009 I *think* you are correct. If I had to guess, I'd do with it's an old da...

"Saaa" <empty needmail.com> writes:

const char[] re1 = `(re)1`;
const char[] re2 = `(re)2`;
char[] matchWrite(RegExp re)
{
writefln(re.match(1),`,`,re.match(2));
return "";
}
std.regexp.sub(`re1 re2`, re1~'|'~re2, &matchWrite, "g");

--- prints
re,
re,re // shouldn't this be `,re`? 

BCS <ao pathlink.com> writes:

Reply to Saaa,

 const char[] re1 = `(re)1`;
 const char[] re2 = `(re)2`;
 char[] matchWrite(RegExp re)
 {
 writefln(re.match(1),`,`,re.match(2));
 return "";
 }
 std.regexp.sub(`re1 re2`, re1~'|'~re2, &matchWrite, "g");
 --- prints
 re,
 re,re // shouldn't this be `,re`?

I *think* you are correct. If I had to guess, I'd do with it's an old data 
issue.