• Lubos Pintes (9/9) Jan 11 2013 Hi,
• evilrat (22/31) Jan 11 2013 what is the definition of format of "array" to read from file?
• evilrat (4/4) Jan 11 2013 oops, for reading by line it is not std.file.byLine but
• monarch_dodra (47/79) Jan 11 2013 Brrr....

Lubos Pintes <lubos.pintes gmail.com> writes:

Hi,
Do I correctly suppose this is not possible? Because I don't understand 
fully the compiler error.

import std.stdio;
void main() {
   int[] a;
   stdin.readf(" %s",&a);
   writeln(a);
}

"evilrat" <evilrat666 gmail.com> writes:

On Friday, 11 January 2013 at 09:44:31 UTC, Lubos Pintes wrote:
 Hi,
 Do I correctly suppose this is not possible? Because I don't 
 understand fully the compiler error.

 import std.stdio;
 void main() {
   int[] a;
   stdin.readf(" %s",&a);
   writeln(a);
 }

what is the definition of format of "array" to read from file?

from your example it is reading formatted(%s = simply any string 
terminated by enter, also prepended by a space?) from standard 
input.

try something like this

import std.file, std.ascii;

void read()
{
// reads whole file to string, use std.file.byLine or others on 
large files
auto data = cast(string) read("path_to_file");

// array storing your data
int[] numbers;

// run through the all content readed from file
foreach(ch; data)
{
// if character is a number put it to numbers array
if ( std.ascii.isNumber(ch) )
   numbers ~= cast(int) ch;
}

}

"evilrat" <evilrat666 gmail.com> writes:

oops, for reading by line it is not std.file.byLine but 
std.stdio.File.byLine



well, use docs, there are lot of info for starters

"monarch_dodra" <monarchdodra gmail.com> writes:

On Friday, 11 January 2013 at 12:17:32 UTC, evilrat wrote:
 On Friday, 11 January 2013 at 09:44:31 UTC, Lubos Pintes wrote:
 Hi,
 Do I correctly suppose this is not possible? Because I don't 
 understand fully the compiler error.

 import std.stdio;
 void main() {
  int[] a;
  stdin.readf(" %s",&a);
  writeln(a);
 }

 what is the definition of format of "array" to read from file?

 from your example it is reading formatted(%s = simply any 
 string terminated by enter, also prepended by a space?) from 
 standard input.

 try something like this

 import std.file, std.ascii;

 void read()
 {
 // reads whole file to string, use std.file.byLine or others on 
 large files
 auto data = cast(string) read("path_to_file");

 // array storing your data
 int[] numbers;

 // run through the all content readed from file
 foreach(ch; data)
 {
 // if character is a number put it to numbers array
 if ( std.ascii.isNumber(ch) )
   numbers ~= cast(int) ch;
 }

 }

Brrr....

Don't parse data yourself! Your code, for example, will only 
parse digits single digits, and will parse "25" as [2, 5]...

Use conv.to !

If your input is an actual array format, you can simply do this:

//----
import std.stdio;
import std.conv;
import std.string;

void main()
{
     auto file = File("data.txt", "r");
     foreach (line; file.byLine())
     {
         auto numbers = to!(int[])(line.strip());
         writeln(numbers);
     }
}
//----

Here is another approach, that will split your input into strings 
that only contains digits, and as such, can be parsed:
//----
import std.stdio;
import std.conv;
import std.algorithm;
import std.array;
import std.ascii;

void main()
{
     auto app = appender!(int[])();
     auto file = File("data.txt", "r");
     foreach (line; file.byLine())
     {
         auto stringEntries = 
std.algorithm.splitter!"!std.ascii.isDigit(a)"(line);
         auto numberEntries = 
stringEntries.filter!"!a.empty"().map!"to!int(a)"();
         app.put(numberEntries);
     }
     writeln(app.data);
}
//----
Even this approach is kind of hackish though, and will not 
support numbers in hex format for example, or floats either. But 
that's the best you get for a completely generic parser that has 
no information on format what so ever.