digitalmars.D.learn - Re: expected array behaviour
- Mike James <foo bar.com> Jan 01 2009
Got it - so I should do this... const char[] array1= "ABCDEFGHIJKLMNOPQRSTUVWXYZ"; char[] array2 = new char[array1.length]; and then copy the contents of array1 into array2. Regards, -=mike=-
Jan 01 2009
On Thu, Jan 1, 2009 at 7:10 PM, Mike James <foo bar.com> wrote:Got it - so I should do this... const char[] array1= "ABCDEFGHIJKLMNOPQRSTUVWXYZ"; char[] array2 = new char[array1.length];
Just "char[] array2 = array1.dup;" .dup duplicates the array by creating a new array the same length and copying the data over.
Jan 01 2009








"Jarrett Billingsley" <jarrett.billingsley gmail.com>