• Joseph Rushton Wakeling (12/12) Jul 04 2013 Suppose I've got a function that is conditional on a type:
• Dicebot (7/8) Jul 04 2013 Each has own disadvantages, chose one ;)
• monarch_dodra (5/20) Jul 04 2013 What he said. Or if you don't even have T, use

Joseph Rushton Wakeling <joseph.wakeling webdrake.net> writes:

Suppose I've got a function that is conditional on a type:

    void foo(T)(/* input vars */) { ... }

How could I print out using writeln the name of that type?  So that if I call

    foo!double(...);

... I would see:

    Today, Michael, I'm going to be a double!

... whereas if I give it,

    foo!uint(...);

I'd see

    Today, Michael, I'm going to be a uint!

and so on.  Ideally this should also work for complex data types such as
structs, classes, etc.

"Dicebot" <public dicebot.lv> writes:

On Thursday, 4 July 2013 at 14:46:36 UTC, Joseph Rushton Wakeling 
wrote:
 ...

Each has own disadvantages, chose one ;)

T.stringof // simple & reliable, won't work for function aliases
__traits(identifier, T) // only symbols
std.traits.fullyQualifiedName!T // issues with templated types, 
includes module/package into name

"monarch_dodra" <monarchdodra gmail.com> writes:

On Thursday, 4 July 2013 at 14:51:21 UTC, Artur Skawina wrote:
 On 07/04/13 16:46, Joseph Rushton Wakeling wrote:
 Suppose I've got a function that is conditional on a type:
 
     void foo(T)(/* input vars */) { ... }
 
 How could I print out using writeln the name of that type?  So 
 that if I call
 
     foo!double(...);
 
 ... I would see:
 
     Today, Michael, I'm going to be a double!

     writeln("Today, Michael, I'm going to be a "~T.stringof~"!")

 artur

What he said. Or if you don't even have T, use 
"typeof(t).stringof".

This also works in pragma msg:
pragma(msg, T.stringof);