• Jude Young (4/4) Nov 05 2011 icon = *(toStringz(text(num)));
• Vladimir Panteleev (8/12) Nov 05 2011 If I understood the problem correctly:
• bearophile (10/13) Nov 05 2011 Are you trying to convert a single-digit number?
• Jude Young (7/20) Nov 05 2011 Nice. Exactly what I was looking for.
• Regan Heath (8/30) Nov 07 2011 You've also got std.ascii.digits which is "0123456789" and
• Dejan Lekic (3/11) Nov 07 2011 I used similar solution to bearophile's before. I must admit i did not k...

Jude Young <10equals2 gmail.com> writes:

icon = *(toStringz(text(num)));

icon is a char, num is an integer.
I don't suppose there is an easier way to do this?

It's too late and ma brains is mushy.

"Vladimir Panteleev" <vladimir thecybershadow.net> writes:

On Sat, 05 Nov 2011 10:29:36 +0200, Jude Young <10equals2 gmail.com> wrote:

 icon = *(toStringz(text(num)));

 icon is a char, num is an integer.
 I don't suppose there is an easier way to do this?

 It's too late and ma brains is mushy.

If I understood the problem correctly:

icon = text(num)[0];

-- or --

icon = cast(char)('0' + num);

-- 
Best regards,
  Vladimir                            mailto:vladimir thecybershadow.net

bearophile <bearophileHUGS lycos.com> writes:

Jude Young:

 icon = *(toStringz(text(num)));
 
 icon is a char, num is an integer.

Are you trying to convert a single-digit number?

import std.stdio;
void main() {
    int x = 5; // in [0 .. 10]
    char c = cast(char)(x + '0');
    writeln(c);
}

Bye,
bearophile

Jude Young <10equals2 gmail.com> writes:

Nice.  Exactly what I was looking for.
I knew I was missing something tiny.

Now I just need to figure out why that works and I can say I've learned
something!
Thanks guys,
Jude

On Sat, Nov 5, 2011 at 5:38 AM, bearophile <bearophileHUGS lycos.com> wrote:

 Jude Young:

 icon = *(toStringz(text(num)));

 icon is a char, num is an integer.

 Are you trying to convert a single-digit number?

 import std.stdio;
 void main() {
    int x = 5; // in [0 .. 10]
    char c = cast(char)(x + '0');
    writeln(c);
 }

 Bye,
 bearophile

"Regan Heath" <regan netmail.co.nz> writes:

On Sun, 06 Nov 2011 04:39:28 -0000, Jude Young <10equals2 gmail.com> wrote:
 Nice.  Exactly what I was looking for.
 I knew I was missing something tiny.

 Now I just need to figure out why that works and I can say I've learned
 something!
 Thanks guys,
 Jude

 On Sat, Nov 5, 2011 at 5:38 AM, bearophile <bearophileHUGS lycos.com>  
 wrote:

 Jude Young:

 icon = *(toStringz(text(num)));

 icon is a char, num is an integer.

 Are you trying to convert a single-digit number?

 import std.stdio;
 void main() {
    int x = 5; // in [0 .. 10]
    char c = cast(char)(x + '0');
    writeln(c);
 }


You've also got std.ascii.digits which is "0123456789" and  
std.string.digits which is an alias of it, so you can say:

import std.ascii; (or std.string)

int x = 5;
char c = std.ascii.digits[x];

-- 
Using Opera's revolutionary email client: http://www.opera.com/mail/

Dejan Lekic <dejan.lekic gmail.com> writes:

Regan Heath wrote:

 You've also got std.ascii.digits which is "0123456789" and
 std.string.digits which is an alias of it, so you can say:
 
 import std.ascii; (or std.string)
 
 int x = 5;
 char c = std.ascii.digits[x];
 

I used similar solution to bearophile's before. I must admit i did not know 
about std.ascii.digits[], thanks for the info Regan.