• berni (12/12) Aug 24 2019 I've got two associative arrays and want to get a new one, which
• a11e99z (2/14) Aug 24 2019 auto ab = a.byPair.chain( b.byPair).assocArray ?
• berni (2/3) Aug 24 2019 Not sure, if it is simpler, but a least without tmp. :) Thanks.

berni <someone somewhere.com> writes:

I've got two associative arrays and want to get a new one, which 
is created out of both of them:

This works:

string[int] a = [1:"one", 7:"seven"];
string[int] b = [5:"five", 9:"nine"];

string[int] tmp = a.dup;
foreach (k,v;b) tmp[k] = v;

assert(tmp==[1:"one", 7:"seven", 5:"five", 9:"nine"]);

But is there something easier, especially without making that 
"tmp" explicit. I hoped for a~b, but that didn't work. (I 
allready know, that there aren't duplicated keys, if that 
matters.)

a11e99z <black80 bk.ru> writes:

On Saturday, 24 August 2019 at 19:35:25 UTC, berni wrote:
 I've got two associative arrays and want to get a new one, 
 which is created out of both of them:

 This works:

 string[int] a = [1:"one", 7:"seven"];
 string[int] b = [5:"five", 9:"nine"];

 string[int] tmp = a.dup;
 foreach (k,v;b) tmp[k] = v;

 assert(tmp==[1:"one", 7:"seven", 5:"five", 9:"nine"]);

 But is there something easier, especially without making that 
 "tmp" explicit. I hoped for a~b, but that didn't work. (I 
 allready know, that there aren't duplicated keys, if that 
 matters.)

auto ab = a.byPair.chain( b.byPair).assocArray ?

berni <someone somewhere.com> writes:

On Saturday, 24 August 2019 at 19:55:48 UTC, a11e99z wrote:
 auto ab = a.byPair.chain( b.byPair).assocArray ?

Not sure, if it is simpler, but a least without tmp. :) Thanks.