• Paul (8/8) May 04 2015 Can some one tell me what this linker command means (or point me
• Kagamin (2/2) May 05 2015 It compiles the example code and links it with supplied
• wobbles (6/14) May 06 2015 I'm guessing this command is to be called from a script
• Paul (10/29) May 06 2015 The script in its entirety is:
• anonymous (2/4) May 06 2015 Passes '-L.' to the linker.
• Paul (2/6) May 06 2015 :D I can see that, but what does '-L.' mean exactly?
• Paul (3/10) May 06 2015 Ah, looks like 'all libraries in current directory'...
• Justin Whear (3/11) May 06 2015 It adds '.' to the list of directories which the linker will search when...
• anonymous (3/10) May 06 2015 If the linker in question is ld, try `ld --help | grep \\-L` or
• Paul (2/13) May 06 2015 Thanks both, got it.

"Paul" <paul example.com> writes:

Can some one tell me what this linker command means (or point me 
at some docs) please:

dmd example.d -L-L. $ 

AFAIK $  is 'all the supplied arguments' so I don't understand 
what it achieves.

(it's from the DAllegro5 example program, on Linux).

Cheers,

Paul

"Kagamin" <spam here.lot> writes:

It compiles the example code and links it with supplied 
libraries, supposedly dallegro bindings.

"wobbles" <grogan.colin gmail.com> writes:

On Monday, 4 May 2015 at 20:34:32 UTC, Paul wrote:
 Can some one tell me what this linker command means (or point 
 me at some docs) please:

 dmd example.d -L-L. $ 

 AFAIK $  is 'all the supplied arguments' so I don't understand 
 what it achieves.

 (it's from the DAllegro5 example program, on Linux).

 Cheers,

 Paul

I'm guessing this command is to be called from a script 
somewhere. So then it will just pass all the arguments passed to 
that script to dmd.

Cant really tell without more info on how it's called, but that's 
what it'll do.

"Paul" <paul example.com> writes:

On Wednesday, 6 May 2015 at 12:41:21 UTC, wobbles wrote:
 On Monday, 4 May 2015 at 20:34:32 UTC, Paul wrote:
 Can some one tell me what this linker command means (or point 
 me at some docs) please:

 dmd example.d -L-L. $ 

 AFAIK $  is 'all the supplied arguments' so I don't understand 
 what it achieves.

 (it's from the DAllegro5 example program, on Linux).

 Cheers,

 Paul

 I'm guessing this command is to be called from a script 
 somewhere. So then it will just pass all the arguments passed 
 to that script to dmd.

 Cant really tell without more info on how it's called, but 
 that's what it'll do.

The script in its entirety is:


dmd -release -ofexample example.d -L-L. $ 

I can compile from the prompt directly with
dmd example.d -L-L.

but I don't understand the syntax. dmd --help mentions 
-Llinkerflag but what is '-L-L.' doing??

TIA

Paul

"anonymous" <anonymous example.com> writes:

On Wednesday, 6 May 2015 at 19:26:40 UTC, Paul wrote:
 but I don't understand the syntax. dmd --help mentions 
 -Llinkerflag but what is '-L-L.' doing??

Passes '-L.' to the linker.

"Paul" <paul example.com> writes:

On Wednesday, 6 May 2015 at 19:30:33 UTC, anonymous wrote:
 On Wednesday, 6 May 2015 at 19:26:40 UTC, Paul wrote:
 but I don't understand the syntax. dmd --help mentions 
 -Llinkerflag but what is '-L-L.' doing??

 Passes '-L.' to the linker.

:D I can see that, but what does '-L.' mean exactly?

"Paul" <paul example.com> writes:

On Wednesday, 6 May 2015 at 19:52:44 UTC, Paul wrote:
 On Wednesday, 6 May 2015 at 19:30:33 UTC, anonymous wrote:
 On Wednesday, 6 May 2015 at 19:26:40 UTC, Paul wrote:
 but I don't understand the syntax. dmd --help mentions 
 -Llinkerflag but what is '-L-L.' doing??

 Passes '-L.' to the linker.

 :D I can see that, but what does '-L.' mean exactly?

Ah, looks like 'all libraries in current directory'...

http://stackoverflow.com/questions/5054833/using-external-library-in-d

Justin Whear <justin economicmodeling.com> writes:

On Wed, 06 May 2015 19:52:42 +0000, Paul wrote:

 On Wednesday, 6 May 2015 at 19:30:33 UTC, anonymous wrote:
 On Wednesday, 6 May 2015 at 19:26:40 UTC, Paul wrote:
 but I don't understand the syntax. dmd --help mentions -Llinkerflag
 but what is '-L-L.' doing??

 Passes '-L.' to the linker.

 
 :D I can see that, but what does '-L.' mean exactly?

It adds '.' to the list of directories which the linker will search when 
looking for the required libraries.

"anonymous" <anonymous example.com> writes:

On Wednesday, 6 May 2015 at 19:52:44 UTC, Paul wrote:
 On Wednesday, 6 May 2015 at 19:30:33 UTC, anonymous wrote:
 On Wednesday, 6 May 2015 at 19:26:40 UTC, Paul wrote:
 but I don't understand the syntax. dmd --help mentions 
 -Llinkerflag but what is '-L-L.' doing??

 Passes '-L.' to the linker.

 :D I can see that, but what does '-L.' mean exactly?

If the linker in question is ld, try `ld --help | grep \\-L` or 
`man ld`.

"Paul" <paul example.com> writes:

On Wednesday, 6 May 2015 at 20:03:36 UTC, anonymous wrote:
 On Wednesday, 6 May 2015 at 19:52:44 UTC, Paul wrote:
 On Wednesday, 6 May 2015 at 19:30:33 UTC, anonymous wrote:
 On Wednesday, 6 May 2015 at 19:26:40 UTC, Paul wrote:
 but I don't understand the syntax. dmd --help mentions 
 -Llinkerflag but what is '-L-L.' doing??

 Passes '-L.' to the linker.

 :D I can see that, but what does '-L.' mean exactly?

 If the linker in question is ld, try `ld --help | grep \\-L` or 
 `man ld`.

Thanks both, got it.