• bearophile (12/12) Jun 17 2011 This is a known bug, right?
• Jonathan M Davis (10/22) Jun 17 2011 You probably have to set the whole array at once. The array's elements _...
• bearophile (13/18) Jun 17 2011 Don't worry, I have defined the array of length one just because I like ...
• Jonathan M Davis (4/28) Jun 17 2011 Then that's a problem, since that makes initializing the array dynamical...

bearophile <bearophileHUGS lycos.com> writes:

This is a known bug, right?


struct Foo {
    const char cc;
    const char[1] array;
    this(char c) {
        cc = c;       // OK
        array[0] = c; // Error: this.array[0] isn't mutable
    }
}
void main() {}


Bye,
bearophile

Jonathan M Davis <jmdavisProg gmx.com> writes:

On 2011-06-17 17:09, bearophile wrote:
 This is a known bug, right?
 
 
 struct Foo {
     const char cc;
     const char[1] array;
     this(char c) {
         cc = c;       // OK
         array[0] = c; // Error: this.array[0] isn't mutable
     }
 }
 void main() {}

You probably have to set the whole array at once. The array's elements _are_ 
const after all. In every other place that you want to initialize a const or 
immutable array, you have to do it all at once. I don't see why this would be 
any different. Sure, it's a special case where setting that one element sets 
the whole array, but making that work would be special casing for such an 
array and complicate the compiler for little benefit. Now, if

array = [c];

doesn't work, _then_ we have a problem.

- Jonathan M Davis

bearophile <bearophileHUGS lycos.com> writes:

Jonathan M Davis:

Sure, it's a special case where setting that one element sets 
 the whole array, but making that work would be special casing for such an 
 array and complicate the compiler for little benefit.

Don't worry, I have defined the array of length one just because I like to
minimize my examples :-)


 Now, if
 array = [c];
 doesn't work, _then_ we have a problem.

This doesn't compile, nor several variants of it:


struct Foo {
    const char[1] array;
    this(char c) {
        array = [c];
    }
}
void main() {}


Bye,
bearophile

Jonathan M Davis <jmdavisProg gmx.com> writes:

On 2011-06-17 18:18, bearophile wrote:
 Jonathan M Davis:
 
 Sure, it's a special case where setting that one element sets
 
 the whole array, but making that work would be special casing for such an
 array and complicate the compiler for little benefit.

 
 Don't worry, I have defined the array of length one just because I like to
 minimize my examples :-)
 
 Now, if
 array = [c];
 doesn't work, _then_ we have a problem.

 
 This doesn't compile, nor several variants of it:
 
 
 struct Foo {
     const char[1] array;
     this(char c) {
         array = [c];
     }
 }
 void main() {}

Then that's a problem, since that makes initializing the array dynamically 
impossible. Definitely worthy of a bug report.

- Jonathan M Davis