• DMon (17/17) Oct 07 2020 Can isType be used as a condition in an if statement with arrays?
• Paul Backus (10/28) Oct 07 2020 You can do this with `is()` and `typeof()`:
• DMon (5/14) Oct 07 2020 I had previously gotten your example to work along with other

DMon <no mail.com> writes:

Can isType be used as a condition in an if statement with arrays?

import std.stdio;
import std.traits;

void main()
{
     int[5] a = [1,2,3,4,5];

// Something like this:
     if (a == isType!(int[5]))
     {
         write("true");
     }

// This works:
     if (a[0] == isType!(int))
     {
         write("true");
     }
}

Paul Backus <snarwin gmail.com> writes:

On Wednesday, 7 October 2020 at 16:25:33 UTC, DMon wrote:
 Can isType be used as a condition in an if statement with 
 arrays?

 import std.stdio;
 import std.traits;

 void main()
 {
     int[5] a = [1,2,3,4,5];

 // Something like this:
     if (a == isType!(int[5]))
     {
         write("true");
     }

 // This works:
     if (a[0] == isType!(int))
     {
         write("true");
     }
 }

You can do this with `is()` and `typeof()`:

if (is(typeof(a) == int[5]))
{
     write("true");
}

The example you have that "works" is just a coincidence: 
`isType!(int)` evaluates to the boolean value `true` (because 
`int` is, indeed, a type), which compares equal to the integer 
`1`.

DMon <no mail.com> writes:

On Wednesday, 7 October 2020 at 16:39:07 UTC, Paul Backus wrote:
 On Wednesday, 7 October 2020 at 16:25:33 UTC, DMon wrote:
 Can isType be used as a condition in an if statement with 
 arrays?

 You can do this with `is()` and `typeof()`:

 if (is(typeof(a) == int[5]))
 {
     write("true");
 }

 The example you have that "works" is just a coincidence:

I had previously gotten your example to work along with other 
basic properties to enter the if statement and isType in the 
write function.

Thanks for the clarification and the note on the second part.