• Engine Machine (15/15) Aug 09 2016 I try to use a mixin template and redefine some behaviors but D
• =?UTF-8?Q?Ali_=c3=87ehreli?= (19/34) Aug 09 2016 I've come up with the following code from your description. It compiles
• ag0aep6g (25/39) Aug 09 2016 Please post proper code.

Engine Machine <EM EM.com> writes:

I try to use a mixin template and redefine some behaviors but D 
includes both and then I get ambiguity. I was sure I read 
somewhere that when one uses mixin template it won't include what 
is already there?

mixin template X
{
    void foo() { }
}

struct s
{
    mixin template
    void foo() { }
}

I was pretty sure I read somewhere that D would not include the 
foo from the template since it already exists.

=?UTF-8?Q?Ali_=c3=87ehreli?= <acehreli yahoo.com> writes:

On 08/09/2016 03:10 PM, Engine Machine wrote:
 I try to use a mixin template and redefine some behaviors but D includes
 both and then I get ambiguity.

It's not always possible to understand without seeing actual code.

 I was sure I read somewhere that when one
 uses mixin template it won't include what is already there?

 mixin template X
 {
    void foo() { }
 }

 struct s
 {
    mixin template
    void foo() { }
 }

 I was pretty sure I read somewhere that D would not include the foo from
 the template since it already exists.

I've come up with the following code from your description. It compiles 
and prints "from struct" with DMD64 D Compiler v2.071.2-b2:

import std.stdio;

mixin template X() {
     void foo() { writefln("from mixin");}
}

struct s
{
    mixin X;
     void foo() { writefln("from struct"); }
}

void main() {
     auto a = s();
     a.foo();
}

How is your code different?

Ali

ag0aep6g <anonymous example.com> writes:

On 08/10/2016 12:10 AM, Engine Machine wrote:
 I try to use a mixin template and redefine some behaviors but D includes
 both and then I get ambiguity. I was sure I read somewhere that when one
 uses mixin template it won't include what is already there?

 mixin template X
 {
    void foo() { }
 }

 struct s
 {
    mixin template
    void foo() { }
 }

 I was pretty sure I read somewhere that D would not include the foo from
 the template since it already exists.

Please post proper code.

This compiles and calls the foo that's not being mixed in:

----
import std.stdio;

mixin template X()
{
    void foo() { writeln("mixed in"); }
}

struct s
{
    mixin X;
    void foo() { writeln("not mixed in"); }
}

void main()
{
     s obj;
     obj.foo();
}
----

This is in line with the spec, which says: "If the name of a declaration 
in a mixin is the same as a declaration in the surrounding scope, the 
surrounding declaration overrides the mixin one" [1]. That may be what 
you've read.


[1] http://dlang.org/spec/template-mixin.html#mixin_scope