• Robert burner Schadek (8/8) Mar 16 2015 ... from all Unicode characters in an idiomatic D way?
• bearophile (5/6) Mar 16 2015 Perhaps by rejection? I mean, generating a uint, test if it's a
• Robert burner Schadek (2/4) Mar 16 2015 hm, that must not even terminate.
• Gary Willoughby (6/14) Mar 16 2015 I guess it depends on the encoding?
• Robert burner Schadek (8/12) Mar 16 2015 This will not work as the caller has to specify the code range. I
• Panke (8/16) Mar 17 2015 You'll need two things. A uniform distribution of { 0 ... 113,020

"Robert burner Schadek" <rburners gmail.com> writes:

... from all Unicode characters in an idiomatic D way? 
(std.interal.unicode_*)

```
T genUnicodeString(T)(size_t minChars, size_t maxChars) 
if(isSomeString!T) {
     ...
}
```

"bearophile" <bearophileHUGS lycos.com> writes:

Robert burner Schadek:

 ... from all Unicode characters in an idiomatic D way?

Perhaps by rejection? I mean, generating a uint, test if it's a 
character and repeat until the result is true.

Bye,
bearophile

"Robert burner Schadek" <rburners gmail.com> writes:

On Monday, 16 March 2015 at 18:48:29 UTC, bearophile wrote:
 Perhaps by rejection? I mean, generating a uint, test if it's a 
 character and repeat until the result is true.

hm, that must not even terminate.

"Gary Willoughby" <dev nomad.so> writes:

On Monday, 16 March 2015 at 13:33:55 UTC, Robert burner Schadek
wrote:
 ... from all Unicode characters in an idiomatic D way? 
 (std.interal.unicode_*)

 ```
 T genUnicodeString(T)(size_t minChars, size_t maxChars) 
 if(isSomeString!T) {
     ...
 }
 ```

I guess it depends on the encoding?

Some references:
http://stackoverflow.com/questions/23853489/generate-a-random-unicode-string
http://www.bonf.net/2009/01/14/generating-random-unicode-strings-in-c/

"Robert burner Schadek" <rburners gmail.com> writes:

On Monday, 16 March 2015 at 22:19:52 UTC, Gary Willoughby wrote:
 I guess it depends on the encoding?

No the character itself are encoding independent.

 Some references:
 http://stackoverflow.com/questions/23853489/generate-a-random-unicode-string

This will not work as the caller has to specify the code range. I
want to specify the string length and the random use is not even
uniform (see channel 9 link)
http://channel9.msdn.com/Events/GoingNative/2013/rand-Considered-Harmful


 http://www.bonf.net/2009/01/14/generating-random-unicode-strings-in-c/

I'm not use how that is going to give me the 113,021 unicode
defined characters let alone in a uniform way.

"Panke" <tobias pankrath.net> writes:

On Monday, 16 March 2015 at 13:33:55 UTC, Robert burner Schadek
wrote:
 ... from all Unicode characters in an idiomatic D way? 
 (std.interal.unicode_*)

 ```
 T genUnicodeString(T)(size_t minChars, size_t maxChars) 
 if(isSomeString!T) {
     ...
 }
 ```

You'll need two things. A uniform distribution of { 0 ... 113,020
}, this should be easy using phobos. And a mapping of { 0 ...
113,020 } -> unicode ( or UTFX directly ). Since the unicode
planes or not connected, this might involve some kind of table.

Then just generate your uniform distribution and apply the
mapping.