• John Chapman (9/9) Nov 29 2018 Is there any way to get a string representing a function's exact
• Neia Neutuladh (8/18) Nov 29 2018 typeof(&func).stringof should do it:
• John Chapman (3/21) Nov 29 2018 That does the trick - thanks.

John Chapman <johnch_atms hotmail.com> writes:

Is there any way to get a string representing a function's exact 
signature as declared in the source? I can generate it myself 
using reflection but it might not be 100% verbatim so wanted to 
know if there's anything built in?

   foreach (m; __traits(allMembers, T)) {
     alias member = __traits(getMember, T, m);
     string signature = // Call some function to get "member"'s 
signature as a string
   }

Neia Neutuladh <neia ikeran.org> writes:

On Thu, 29 Nov 2018 21:11:06 +0000, John Chapman wrote:
 Is there any way to get a string representing a function's exact
 signature as declared in the source? I can generate it myself using
 reflection but it might not be 100% verbatim so wanted to know if
 there's anything built in?
 
    foreach (m; __traits(allMembers, T)) {
      alias member = __traits(getMember, T, m);
      string signature = // Call some function to get "member"'s
 signature as a string
    }

typeof(&func).stringof should do it:

    void bar(string s, ref Foo!int i) {}
    void main()
    {
        writeln(typeof(&bar).stringof);
    }

prints: void function(string s, ref Foo!int i)

John Chapman <johnch_atms hotmail.com> writes:

On Thursday, 29 November 2018 at 21:31:57 UTC, Neia Neutuladh 
wrote:
 On Thu, 29 Nov 2018 21:11:06 +0000, John Chapman wrote:
 Is there any way to get a string representing a function's 
 exact signature as declared in the source? I can generate it 
 myself using reflection but it might not be 100% verbatim so 
 wanted to know if there's anything built in?
 
    foreach (m; __traits(allMembers, T)) {
      alias member = __traits(getMember, T, m);
      string signature = // Call some function to get "member"'s
 signature as a string
    }

 typeof(&func).stringof should do it:

     void bar(string s, ref Foo!int i) {}
     void main()
     {
         writeln(typeof(&bar).stringof);
     }

 prints: void function(string s, ref Foo!int i)

That does the trick - thanks.