• TJB (13/13) Jun 12 2012 I am working with some financial data that comes in binary files.
• Jonathan M Davis (11/25) Jun 12 2012 import std.datetime;
• TJB (4/31) Jun 12 2012 Awesome! In the D community you get questions answered by the

"TJB" <broughtj gmail.com> writes:

I am working with some financial data that comes in binary files. 
It has two fields in particular that I am trying to convert to 
human readable formats. The first is a date string like 
"20060621", which I am able to work with just fine. But then it 
has a field called ttim, which is the number of seconds from 
midnight at which a trade occurred. For example, a trade 
occurring at 28824 seconds in the day would have taken place at 
"8:00:24" (only resolution to the second).

My question is: how do I convert the number of seconds (like 
28824) to a formatted time string (like 08:00:24)?  I looked in 
std.datetime, but it isn't obvious which functions I should use.

You help and suggestions are much appreciated!

TJB

"Jonathan M Davis" <jmdavisProg gmx.com> writes:

On Tuesday, June 12, 2012 19:28:38 TJB wrote:
 I am working with some financial data that comes in binary files.
 It has two fields in particular that I am trying to convert to
 human readable formats. The first is a date string like
 "20060621", which I am able to work with just fine. But then it
 has a field called ttim, which is the number of seconds from
 midnight at which a trade occurred. For example, a trade
 occurring at 28824 seconds in the day would have taken place at
 "8:00:24" (only resolution to the second).
 
 My question is: how do I convert the number of seconds (like
 28824) to a formatted time string (like 08:00:24)? I looked in
 std.datetime, but it isn't obvious which functions I should use.
 
 You help and suggestions are much appreciated!

import std.datetime;
import std.stdio;

void main()
{
 auto ttm = 28824;
 auto duration = dur!"seconds"(ttm);
 auto time = TimeOfDay.init + duration;
 writeln(time.toISOExtString());
}

- Jonathan M Davis

"TJB" <broughtj gmail.com> writes:

On Tuesday, 12 June 2012 at 17:40:40 UTC, Jonathan M Davis wrote:
 On Tuesday, June 12, 2012 19:28:38 TJB wrote:
 I am working with some financial data that comes in binary 
 files.
 It has two fields in particular that I am trying to convert to
 human readable formats. The first is a date string like
 "20060621", which I am able to work with just fine. But then it
 has a field called ttim, which is the number of seconds from
 midnight at which a trade occurred. For example, a trade
 occurring at 28824 seconds in the day would have taken place at
 "8:00:24" (only resolution to the second).
 
 My question is: how do I convert the number of seconds (like
 28824) to a formatted time string (like 08:00:24)? I looked in
 std.datetime, but it isn't obvious which functions I should 
 use.
 
 You help and suggestions are much appreciated!

 import std.datetime;
 import std.stdio;

 void main()
 {
  auto ttm = 28824;
  auto duration = dur!"seconds"(ttm);
  auto time = TimeOfDay.init + duration;
  writeln(time.toISOExtString());
 }

 - Jonathan M Davis

Awesome! In the D community you get questions answered by the 
library writers!  Thanks so much! This was perfect.

TJB