• Doctor J (40/40) Apr 12 2009 I want to test whether a struct member is a real field or a property at ...
• Doctor J (4/4) Apr 12 2009 Answered my own question:
• bearophile (6/9) Apr 12 2009 What you may want is to test if a type is a callable (function, delegate...
• Lars Kyllingstad (12/18) Apr 13 2009 You say you want to test whether a struct/class member is a field or a

Doctor J <nobody nowhere.com> writes:

I want to test whether a struct member is a real field or a property at compile
time.  I thought this is what is(type == function) is supposed to do, but I
can't find anything that will make is(type == function) true.  What am I doing
wrong?

----------------------------------------------
import std.stdio;

int func0()
{
    return 0;
}

int func1(int x)
{
    return x;
}

int main()
{
    static if (is(func0))
        writefln("func0 is semantically correct.");
    static if (is(func0 == function))
        writefln("func0 is a function.");
    else
        writefln("func0 is NOT a function.");
    writefln("typeof(func0): %s\n", typeof(func0).stringof);
    
    static if (is (func0()))
        writefln("func0() is semantically correct.");
    static if (is(func0() == function))
        writefln("func0() is a function.");
    else
        writefln("func0() is NOT a function.");
    writefln("typeof(func0()): %s", typeof(func0()).stringof);
    
    // And for good measure, this one doesn't even compile; why is that?
    // writefln("typeof(func1): %s", typeof(func1).stringof);   
    return 0;
}
------------------------------------------

This outputs:

func0 is NOT a function.
typeof(func0): (int())()

func0() is NOT a function.
typeof(func0()): int



Oh, and I'm using Phobos 1.0 with gdc.  :)

Doctor J <nobody nowhere.com> writes:

Answered my own question:

    static if (is(typeof(func0) == function))
        writefln("func0 is a function.");

is() really wants a type, not an expression.

bearophile <bearophileHUGS lycos.com> writes:

Doctor J:
     static if (is(typeof(func0) == function))
         writefln("func0 is a function.");
 is() really wants a type, not an expression.

What you may want is to test if a type is a callable (function, delegate or
object with opCall).
See IsCallable here:
http://www.fantascienza.net/leonardo/so/dlibs/templates.html

Bye,
bearophile

Lars Kyllingstad <public kyllingen.NOSPAMnet> writes:

Doctor J wrote:
 Answered my own question:
 
     static if (is(typeof(func0) == function))
         writefln("func0 is a function.");
 
 is() really wants a type, not an expression.

You say you want to test whether a struct/class member is a field or a 
property. Pointers to class and struct methods are delegates, not 
function pointers.

     http://www.digitalmars.com/d/1.0/type.html#delegates

So the correct thing to write would be:

     static if (is(typeof(func0) == delegate)) { ... }

or, to test whether func0 is a function OR a delegate,

     static if (is(typeof(func0) == return)) { ... }

For details, see
     http://www.digitalmars.com/d/1.0/expression.html#IsExpression

-Lars