digitalmars.D.learn - Delegate contravariance
- Silvio Ricardo Cordeiro (19/19) Jan 13 2009 Is there any good reason why the following code doesn't work?
- Steven Schveighoffer (8/27) Jan 13 2009 I think it would be a worthy enhancement, but it currently isn't impleme...
- BCS (4/5) Jan 13 2009 [...]
- Jason House (17/42) Jan 19 2009 Your code above is wrong, but you are right about a bug in dmd.
- Christopher Wright (6/39) Jan 19 2009 No, it implicitly casts Bs (derived) to As (base). The original example
Is there any good reason why the following code doesn't work? The function "foo" requires as its argument a delegate that receives a B. This means that, because of the type soundness of the D language, the delegate will only be called with instances of B. Now, why can't it be "abc", then? The "abc" delegate just happens to handle more than it is required... class A { } class B : A { } void foo(void delegate(B b) dg) {} auto abc = (A a) { } auto qwe = (B b) { } void main() { foo(abc); // this line won't compile foo(qwe); } BTW: Same thing happens for const(B). B "sort of" a derivative of const(B), so it would make sense. Every possible argument that can be passed to a delegate(B) can also be passed to a delegate(A) or delegate(const(B)). Why the restriction, then? Am I missing something?
Jan 13 2009
"Silvio Ricardo Cordeiro" wroteIs there any good reason why the following code doesn't work? The function "foo" requires as its argument a delegate that receives a B. This means that, because of the type soundness of the D language, the delegate will only be called with instances of B. Now, why can't it be "abc", then? The "abc" delegate just happens to handle more than it is required... class A { } class B : A { } void foo(void delegate(B b) dg) {} auto abc = (A a) { } auto qwe = (B b) { } void main() { foo(abc); // this line won't compile foo(qwe); } BTW: Same thing happens for const(B). B "sort of" a derivative of const(B), so it would make sense. Every possible argument that can be passed to a delegate(B) can also be passed to a delegate(A) or delegate(const(B)). Why the restriction, then? Am I missing something?I think it would be a worthy enhancement, but it currently isn't implemented or in the spec. You should add a bugzilla enhancement if it isn't already there. You should be able to cast to get around it, but of course, that is ugly and cumbersome: foo(cast(void delegate(B b))abc); -Steve
Jan 13 2009
Reply to Silvio,Is there any good reason why the following code doesn't work?[...] If you want to dive into template programming you can make a do-nothing function that does the cast and will only compile if the cast is in fact safe.
Jan 13 2009
Silvio Ricardo Cordeiro wrote:Is there any good reason why the following code doesn't work? The function "foo" requires as its argument a delegate that receives a B. This means that, because of the type soundness of the D language, the delegate will only be called with instances of B. Now, why can't it be "abc", then? The "abc" delegate just happens to handle more than it is required... class A { } class B : A { } void foo(void delegate(B b) dg) {} auto abc = (A a) { } auto qwe = (B b) { } void main() { foo(abc); // this line won't compile foo(qwe); } BTW: Same thing happens for const(B). B "sort of" a derivative of const(B), so it would make sense. Every possible argument that can be passed to a delegate(B) can also be passed to a delegate(A) or delegate(const(B)). Why the restriction, then? Am I missing something?Your code above is wrong, but you are right about a bug in dmd. Your code sample should not compile because of two issues: 1. You're missing semicolons on the declarations of abc and qwe. 2. foo(abc) is implicitly requires casting A's to B's which is not guaranteed to be correct. Here is code that should compile but doesn't class A{} class B:A{} void foo(void delegate(A a) dg){} auto abc = (A a){}; auto qwe = (B b){}; void main(){ foo(abc); foo(qwe); } test.d(10): function test.foo (void delegate(A a) dg) does not match parameter types (void delegate(B b)) test.d(10): Error: cannot implicitly convert expression (qwe) of type void delegate(B b) to void delegate(A a)
Jan 19 2009
Jason House wrote:Silvio Ricardo Cordeiro wrote:No, it implicitly casts Bs (derived) to As (base). The original example was correct (modulo semicolon issues). Your example has implicit casts of a base class to a derived class. On the other hand, out parameters and return values have to be handled in the reverse manner, and ref parameters have to use exact matching.Is there any good reason why the following code doesn't work? The function "foo" requires as its argument a delegate that receives a B. This means that, because of the type soundness of the D language, the delegate will only be called with instances of B. Now, why can't it be "abc", then? The "abc" delegate just happens to handle more than it is required... class A { } class B : A { } void foo(void delegate(B b) dg) {} auto abc = (A a) { } auto qwe = (B b) { } void main() { foo(abc); // this line won't compile foo(qwe); } BTW: Same thing happens for const(B). B "sort of" a derivative of const(B), so it would make sense. Every possible argument that can be passed to a delegate(B) can also be passed to a delegate(A) or delegate(const(B)). Why the restriction, then? Am I missing something?Your code above is wrong, but you are right about a bug in dmd. Your code sample should not compile because of two issues: 1. You're missing semicolons on the declarations of abc and qwe. 2. foo(abc) is implicitly requires casting A's to B's which is not guaranteed to be correct.
Jan 19 2009