• Simen Haugen (12/12) Feb 02 2007 I thought that if I create a struct in a loop, a new struct would be cre...
• Frits van Bommel (26/41) Feb 02 2007 It *is* a new struct each time:
• Simen Haugen (3/7) Feb 02 2007 I see. I stored the pointer in another array, so I thought it wouldn't g...
• BCS (3/7) Feb 02 2007 exactly, struct are stored like ints, on the stack and accessing them is...
• torhu (11/27) Feb 02 2007 be created each time, but if you see below, it's the same object. How

Simen Haugen <simen norstat.no> writes:

I thought that if I create a struct in a loop, a new struct would be created
each time, but if you see below, it's the same object. How can I create a new
struct each iteration?

import std.stdio;

struct Test
{}

void main()
{
	for (int i=0;i < 2; i++)
	{
		Test t;
		writefln("Pointer: ", cast(int)&t);
	}
}

Frits van Bommel <fvbommel REMwOVExCAPSs.nl> writes:

Simen Haugen wrote:
 I thought that if I create a struct in a loop, a new struct would be created
each time, but if you see below, it's the same object. How can I create a new
struct each iteration?
 
 import std.stdio;
 
 struct Test
 {}
 
 void main()
 {
 	for (int i=0;i < 2; i++)
 	{
 		Test t;
 		writefln("Pointer: ", cast(int)&t);
 	}
 }

It *is* a new struct each time:
---
urxae urxae:~/tmp$ cat test.d
import std.stdio;

struct Test
{ int k = 100; }

void main()
{
         for (int i=0;i < 2; i++)
         {
                 Test t;
                 writefln(t.k);
                 t.k = i;
                 writefln("Pointer: ", cast(int)&t);
         }
}
urxae urxae:~/tmp$ dmd -run test.d
100
Pointer: -1077296716
100
Pointer: -1077296716
---

But after each iteration of the loop, the struct used is destroyed, and 
the most convenient place to put the next one happens to be the same 
place as the most convenient place to put the last one...

Simen Haugen <simen norstat.no> writes:

Frits van Bommel Wrote:
 It *is* a new struct each time:

(...)
 But after each iteration of the loop, the struct used is destroyed, and 
 the most convenient place to put the next one happens to be the same 
 place as the most convenient place to put the last one...

I see. I stored the pointer in another array, so I thought it wouldn't go out
of scope. I guess this only works for object allocated on the heap...?

BCS <BCS pathlink.com> writes:

Simen Haugen wrote:
 
 I see. I stored the pointer in another array, so I thought it wouldn't
 go out of scope. I guess this only works for object allocated on the
 heap...?

exactly, struct are stored like ints, on the stack and accessing them is 
invalid after the end of that scope.

torhu <fake address.dude> writes:

Simen Haugen wrote:
 I thought that if I create a struct in a loop, a new struct would 


be created each time, but if you see below, it's the same object. How 
can I create a new struct each iteration?
 import std.stdio;

 struct Test
 {}

 void main()
 {
 	for (int i=0;i < 2; i++)
 	{
 		Test t;
 		writefln("Pointer: ", cast(int)&t);
 	}
 }


A struct is just a regular local variable, ie. allocated on the stack.
Each time 'Test t;' is executed, the same space is initialized. So it's
overwritten, but it doesn't move.  Except that empty structs might not 
get initialized, even though they have a size of one byte.  You can 
allocate on the heap with 'new' if you want each instance to be unique.

Try this:

Test* t = new Test;
writefln("Pointer: ", cast(int)t);