• Straivers (5/5) Oct 09 2015 Forgive me if this has already been discussed, but how are arrays
• anonymous (9/13) Oct 09 2015 no
• Meta (3/9) Oct 09 2015 If you want to compare them with approxEqual, you can do:

Straivers <straivers98 gmail.com> writes:

Forgive me if this has already been discussed, but how are arrays 
of floating point numbers compared in D? i.e. Is it a bit-by-bit 
comparison, is the std.math.approxEqual function get called for 
each element, or is it byte-by-byte across the entire array?

-Straivers

anonymous <anonymous example.com> writes:

On Saturday 10 October 2015 00:14, Straivers wrote:

 Is it a bit-by-bit comparison,

no

 is the std.math.approxEqual function get called for 
 each element,

no

 or is it byte-by-byte across the entire array?

no

After comparing the lengths, the elements are checked for equality one by 
one, using the usual `==` operator.

`==` is different from bitwise comparison. For example, -0f and +0f are `==` 
equal but have different bits, and NaNs are equal no nothing, not even 
themselves.

Meta <jared771 gmail.com> writes:

On Friday, 9 October 2015 at 22:14:09 UTC, Straivers wrote:
 Forgive me if this has already been discussed, but how are 
 arrays of floating point numbers compared in D? i.e. Is it a 
 bit-by-bit comparison, is the std.math.approxEqual function get 
 called for each element, or is it byte-by-byte across the 
 entire array?

 -Straivers

If you want to compare them with approxEqual, you can do:

arr1.equal!approxEqual(arr2)