• Shigeki Karita (14/14) Jun 26 2018 import std.stdio;
• Shigeki Karita (18/32) Jun 26 2018 I found that formattedRead!"%d\n"(readln(), i) can avoid the

Shigeki Karita <shigekikarita gmail.com> writes:

import std.stdio;
import std.conv;

void main() {
     int i;
     try {
         readf("%d\n", &i); // "a"
     } catch (ConvException e) {
         auto s = readln();
         writeln(s); // "aa", "aaa" or SEGV ???
     }
}

https://wandbox.org/permlink/NMYNjpOgQtfUprBQ

I just want to retry reading if input was invalid. How can I do 
it?

Shigeki Karita <shigekikarita gmail.com> writes:

On Wednesday, 27 June 2018 at 02:39:49 UTC, Shigeki Karita wrote:
 import std.stdio;
 import std.conv;

 void main() {
     int i;
     try {
         readf("%d\n", &i); // "a"
     } catch (ConvException e) {
         auto s = readln();
         writeln(s); // "aa", "aaa" or SEGV ???
     }
 }

 https://wandbox.org/permlink/NMYNjpOgQtfUprBQ

 I just want to retry reading if input was invalid. How can I do 
 it?


I found that formattedRead!"%d\n"(readln(), i) can avoid the 
buffer overrun why readf cannot do this?

---

import std.stdio;
import std.format;

import std.stdio;
import std.format;

void main() {
     int i;
     try {
         formattedRead!"%d\n"(readln(), i);
     } catch (Exception e) {
         // writeln(e);
         auto s = readln();
         writeln(s); // ""
     }
}