• Markus Dangl (31/31) Feb 25 2007 Hi,

Markus Dangl <danglm in.tum.de> writes:

Hi,
i don't know if this is really a bug, so i'm posting here in the learn 
group.

If there is no sharp in the string to search, the whole first subpattern 
won't match, so it captures nothing (an empty string). So the subpattern 
(\\w) shouldn't capture anything, either, right?

I tested it with the following code:
------------------------------------
import std.stdio;
import std.regexp;

int main(char[][] args)
{

     if (m is null) { writefln("Doesn't match"); return 0; }
     for (int i=0;i<6;i++)
         writefln("%d: %s", i, m.match(i));
     return 0;
}
------------------------------------
Which displays:
0: test
1:
2: t
3: test
4:
5:


I don't really know the regexp implementation, but i assume it doesn't 
throw away previously captured subpatterns after it encounters the